📄 porterstemmer.java
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package dragon.nlp.tool;
import java.io.*;
/**
* <p>Porter stemmer</p>
* <p> </p>
* <p>Copyright: Copyright (c) 2005</p>
* <p>Company: IST, Drexel University</p>
* @author Davis Zhou
* @version 1.0
*/
public class PorterStemmer implements Lemmatiser{
private char[] b;
private int i, /* offset into b */
i_end, /* offset to end of stemmed word */
j, k;
private static final int INC = 50;
/* unit of size whereby b is increased */
public PorterStemmer() {
b = new char[INC];
i = 0;
i_end = 0;
}
/*added by davis*/
public String stem(String word){
for(int i=0;i<word.length();i++)
add(word.charAt(i));
stem();
return toString();
}
public String lemmatize(String word){
return stem(word);
}
public String lemmatize(String word, int POS){
return stem(word);
}
//ended
/**
* Add a character to the word being stemmed. When you are finished
* adding characters, you can call stem(void) to stem the word.
*/
public void add(char ch) {
if (i == b.length) {
char[] new_b = new char[i + INC];
for (int c = 0; c < i; c++) {
new_b[c] = b[c];
}
b = new_b;
}
b[i++] = ch;
}
/** Adds wLen characters to the word being stemmed contained in a portion
* of a char[] array. This is like repeated calls of add(char ch), but
* faster.
*/
public void add(char[] w, int wLen) {
if (i + wLen >= b.length) {
char[] new_b = new char[i + wLen + INC];
for (int c = 0; c < i; c++) {
new_b[c] = b[c];
}
b = new_b;
}
for (int c = 0; c < wLen; c++) {
b[i++] = w[c];
}
}
/**
* After a word has been stemmed, it can be retrieved by toString(),
* or a reference to the internal buffer can be retrieved by getResultBuffer
* and getResultLength (which is generally more efficient.)
*/
public String toString() {
return new String(b, 0, i_end);
}
/**
* Returns the length of the word resulting from the stemming process.
*/
public int getResultLength() {
return i_end;
}
/**
* Returns a reference to a character buffer containing the results of
* the stemming process. You also need to consult getResultLength()
* to determine the length of the result.
*/
public char[] getResultBuffer() {
return b;
}
/* cons(i) is true <=> b[i] is a consonant. */
private final boolean cons(int i) {
switch (b[i]) {
case 'a':
case 'e':
case 'i':
case 'o':
case 'u':
return false;
case 'y':
return (i == 0) ? true : !cons(i - 1);
default:
return true;
}
}
/* m() measures the number of consonant sequences between 0 and j. if c is
a consonant sequence and v a vowel sequence, and <..> indicates arbitrary
presence,
<c><v> gives 0
<c>vc<v> gives 1
<c>vcvc<v> gives 2
<c>vcvcvc<v> gives 3
....
*/
private final int m() {
int n = 0;
int i = 0;
while (true) {
if (i > j) {
return n;
}
if (!cons(i)) {
break;
}
i++;
}
i++;
while (true) {
while (true) {
if (i > j) {
return n;
}
if (cons(i)) {
break;
}
i++;
}
i++;
n++;
while (true) {
if (i > j) {
return n;
}
if (!cons(i)) {
break;
}
i++;
}
i++;
}
}
/* vowelinstem() is true <=> 0,...j contains a vowel */
private final boolean vowelinstem() {
int i;
for (i = 0; i <= j; i++) {
if (!cons(i)) {
return true;
}
}
return false;
}
/* doublec(j) is true <=> j,(j-1) contain a double consonant. */
private final boolean doublec(int j) {
if (j < 1) {
return false;
}
if (b[j] != b[j - 1]) {
return false;
}
return cons(j);
}
/* cvc(i) is true <=> i-2,i-1,i has the form consonant - vowel - consonant
and also if the second c is not w,x or y. this is used when trying to
restore an e at the end of a short word. e.g.
cav(e), lov(e), hop(e), crim(e), but
snow, box, tray.
*/
private final boolean cvc(int i) {
if (i < 2 || !cons(i) || cons(i - 1) || !cons(i - 2)) {
return false;
}
{
int ch = b[i];
if (ch == 'w' || ch == 'x' || ch == 'y') {
return false;
}
}
return true;
}
private final boolean ends(String s) {
int l = s.length();
int o = k - l + 1;
if (o < 0) {
return false;
}
for (int i = 0; i < l; i++) {
if (b[o + i] != s.charAt(i)) {
return false;
}
}
j = k - l;
return true;
}
/* setto(s) sets (j+1),...k to the characters in the string s, readjusting
k. */
private final void setto(String s) {
int l = s.length();
int o = j + 1;
for (int i = 0; i < l; i++) {
b[o + i] = s.charAt(i);
}
k = j + l;
}
/* r(s) is used further down. */
private final void r(String s) {
if (m() > 0) {
setto(s);
}
}
/* step1() gets rid of plurals and -ed or -ing. e.g.
caresses -> caress
ponies -> poni
ties -> ti
caress -> caress
cats -> cat
feed -> feed
agreed -> agree
disabled -> disable
matting -> mat
mating -> mate
meeting -> meet
milling -> mill
messing -> mess
meetings -> meet
*/
private final void step1() {
if (b[k] == 's') {
if (ends("sses")) {
k -= 2;
}
else
if (ends("ies")) {
setto("i");
}
else
if (b[k - 1] != 's') {
k--;
}
}
if (ends("eed")) {
if (m() > 0) {
k--;
}
}
else
if ( (ends("ed") || ends("ing")) && vowelinstem()) {
k = j;
if (ends("at")) {
setto("ate");
}
else
if (ends("bl")) {
setto("ble");
}
else
if (ends("iz")) {
setto("ize");
}
else
if (doublec(k)) {
k--;
{
int ch = b[k];
if (ch == 'l' || ch == 's' || ch == 'z') {
k++;
}
}
}
else if (m() == 1 && cvc(k)) {
setto("e");
}
}
}
/* step2() turns terminal y to i when there is another vowel in the stem. */
private final void step2() {
if (ends("y") && vowelinstem()) {
b[k] = 'i';
}
}
/* step3() maps double suffices to single ones. so -ization ( = -ize plus
-ation) maps to -ize etc. note that the string before the suffix must give
m() > 0. */
private final void step3() {
if (k == 0) {
return; /* For Bug 1 */
}
switch (b[k - 1]) {
case 'a':
if (ends("ational")) {
r("ate");
break;
}
if (ends("tional")) {
r("tion");
break;
}
break;
case 'c':
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