📄 ip_06_03.m
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% MATLAB script for Illustrative Problem 3, Chapter 6.echo onf_cutoff=2000; % the desired cut-off frequencyf_stopband=2500; % the actual stopband frequencyfs=10000; % the sampling frequencyf1=2*f_cutoff/fs; % the normalized passband frequencyf2=2*f_stopband/fs; % the normalized stopband frequencyN=41; % this number is found by experimentF=[0 f1 f2 1]; M=[1 1 0 0]; % describes the low-pass filterB=remez(N-1,F,M); % returns the FIR tap coefficients% plotting command followsfigure(1);[H,W]=freqz(B);H_in_dB=20*log10(abs(H));plot(W/(2*pi),H_in_dB);figure(2);plot(W/(2*pi),(180/pi)*unwrap(angle(H)));% plot of the impulse response followsfigure(3);plot(zeros(size([0:N-1])));hold;stem([0:N-1],B);
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