📄 lp_maker.m
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%LP_MAKER Makes mixed integer linear programming problems.%% SYNOPSIS: lp_handle = lp_maker(f,a,b,e,vlb,vub,xint,scalemode,setminim)% make the MILP problem% max v = f'*x% a*x <> b% vlb <= x <= vub% x(int) are integer%% ARGUMENTS: The first four arguments are required:% f: n vector of coefficients for a linear objective function.% a: m by n matrix representing linear constraints.% b: m vector of right sides for the inequality constraints.% e: m vector that determines the sense of the inequalities:% e(i) < 0 ==> Less Than% e(i) = 0 ==> Equals% e(i) > 0 ==> Greater Than% vlb: n vector of non-negative lower bounds. If empty or omitted,% then the lower bounds are set to zero.% vub: n vector of upper bounds. May be omitted or empty.% xint: vector of integer variables. May be omitted or empty.% scalemode: Autoscale flag. Off when 0 or omitted.% setminim: Set maximum lp when this flag equals 0 or omitted.%% OUTPUT: lp_handle is an integer handle to the lp created.function lp_handle = lp_maker(f,a,b,e,vlb,vub,xint,scalemode,setminim)if nargin == 0 help lp_maker; return;end[m,n] = size(a);lp_handle = mxlpsolve('make_lp', m, n);mxlpsolve('set_verbose', lp_handle, 3);mxlpsolve('set_mat', lp_handle, a);mxlpsolve('set_rh_vec', lp_handle, b);mxlpsolve('set_obj_fn', lp_handle, f);mxlpsolve('set_maxim', lp_handle); % default is solving minimum lp.for i = 1:length(e) if e(i) < 0 con_type = 1; elseif e(i) == 0 con_type = 3; else con_type = 2; end mxlpsolve('set_constr_type', lp_handle, i, con_type);endif nargin > 4 for i = 1:length(vlb) mxlpsolve('set_lowbo', lp_handle, i, vlb(i)); endendif nargin > 5 for i = 1:length(vub) mxlpsolve('set_upbo', lp_handle, i, vub(i)); endendif nargin > 6 for i = 1:length(xint) mxlpsolve('set_int', lp_handle, xint(i), 1); endendif nargin > 7 if scalemode ~= 0 mxlpsolve('set_scaling', lp_handle, scalemode); endendif nargin > 8 if setminim ~= 0 mxlpsolve('set_minim', lp_handle); else mxlpsolve('set_maxim', lp_handle); endend
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