取每行的频度值函数.txt

一些解决线形方程组的并行计算的程序,希望对大家有一点帮助

#include <stdio.h>
#include <iostream>
#include <math.h>
#include <stdlib.h>
using namespace std;
int main()
{
	FILE *fp;
	//char colnum[num];
    //char rownum[num];
	float linefre[44050];
	long buffer[2];
    long colnumInt=0;
    long rownumInt=0;
    long index2=0;
    float frequency=0;
   // for(int y=0;y<44050;y++)
     // linefre[y]=0;
	//memset(linefre,0,44050);
	//memset(colnum,0,num);
    //memset(rownum,0,num);
	if((fp=fopen("c:/010","rb+"))==NULL)
	{
		cout<<"can not open the file"<<endl;
		exit(0);
	}
	for(int i=0;i<44050;i++)
	{
	//int i=0;
	    fseek(fp,8,1);
		fread(buffer,sizeof(long)*2,1,fp);
		//cout<<buffer[0]<<endl;
		//cout<<buffer[1]<<endl;
		fseek(fp,8*44050-8*(i+1)+buffer[0],1);
		cout<<"第"<<i+1<<"行的频度是："<<endl;
		for(int j=0;j<buffer[1];j++)
		{
			fread(&index2,sizeof(long),1,fp);
			//cout<<index2<<endl;
			fread(&frequency,sizeof(float),1,fp);
			//cout<<frequency<<endl;
			linefre[index2]=frequency;
			cout<<"linefre"<<"["<<index2<<"]"<<"  is  "<<linefre[index2]<<endl;
			
		}
		fseek(fp,-44050*8+8*i-buffer[0]-8*buffer[1],1);
		cout<<endl;
		//for(int h=0;h<4;h++)
		//cout<<linefre[h]<<endl;
	}
	fclose(fp);
	return 0;
	
}