📄 form1.frm
字号:
VERSION 5.00
Begin VB.Form frmSearch
Caption = "Searching a string for a substring"
ClientHeight = 2415
ClientLeft = 60
ClientTop = 345
ClientWidth = 4680
LinkTopic = "Form1"
ScaleHeight = 2415
ScaleWidth = 4680
StartUpPosition = 3 'Windows Default
Begin VB.TextBox txtInput2
Height = 285
Left = 0
TabIndex = 4
Top = 960
Width = 4695
End
Begin VB.TextBox txtInput1
Height = 285
Left = 0
TabIndex = 2
Top = 360
Width = 4695
End
Begin VB.CommandButton cmdSearch
Caption = "Search"
Height = 375
Left = 0
TabIndex = 1
Top = 1320
Width = 1815
End
Begin VB.Label lblOutput2
Height = 255
Left = 0
TabIndex = 6
Top = 2040
Width = 4695
End
Begin VB.Label lblOutput1
Height = 255
Left = 0
TabIndex = 5
Top = 1800
Width = 4695
End
Begin VB.Label lblInput2
Caption = "Enter string to locate in phrase"
Height = 255
Left = 0
TabIndex = 3
Top = 720
Width = 2415
End
Begin VB.Label lblInput1
Caption = "Enter phrase"
Height = 255
Left = 0
TabIndex = 0
Top = 120
Width = 2295
End
End
Attribute VB_Name = "frmSearch"
Attribute VB_GlobalNameSpace = False
Attribute VB_Creatable = False
Attribute VB_PredeclaredId = True
Attribute VB_Exposed = False
' Fig. 8.6
' Using InStr and InStrRev to search a string for a substring
Option Explicit
Private Sub cmdSearch_Click()
Dim forwardResult As Integer, backwardResult As Integer
forwardResult = InStr(txtInput1.Text, txtInput2.Text)
If forwardResult <> 0 Then
lblOutput1.Caption = "Forward search: " & _
"The text was found at position " & forwardResult
Else
lblOutput1.Caption = "Forward search: " & _
"The text was not found"
End If
backwardResult = InStrRev(txtInput1.Text, txtInput2.Text)
If backwardResult <> 0 Then
lblOutput2.Caption = "Backward search: " & _
"The text was found at position " & backwardResult
Else
lblOutput2.Caption = "Backward search: " & _
"The text was not found"
End If
End Sub
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