noname1

通过PROTUES 在矩正8*8上仿真显示汉字的程序

#include<reg51.h>
  #include<absacc.h>


#define   DATBIT1      XBYTE[ 0x0100]
#define   DATBIT2      XBYTE[ 0x0200]
#define   DATBIT3      XBYTE[ 0x0080]
#define   DATBIT4      XBYTE[ 0x0040]
#define   DAT1  XBYTE[ 0x0020]
#define   DAT2  XBYTE[ 0x0010]
#define   DAT3  XBYTE[ 0x0008]
#define   DAT4  XBYTE[ 0x0004]
#define   DAT5  XBYTE[ 0x0002]
#define   DAT6  XBYTE[ 0x0001]
#define   DAT7  XBYTE[ 0x8000]
#define   DAT8  XBYTE[ 0x4000]

#define uchar   unsigned char
#define uint    unsigned int

uchar code TABLE1[]={0x22,0x24,0x3F,0x02,0x01,0x7f,0x01,0x01,0x00,0x21,0x21,0x21,0x21,0x3f,0x21,0x2f};
uchar code TABLE2[]={0x44,0x24,0xfc,0x00,0x00,0xfe,0x04,0x00,0x00,0x08,0x14,0x04,0x04,0xfc,0x04,0xf4};
uchar code TABLE3[]={0x22,0x24,0x3F,0x02,0x01,0x7f,0x01,0x01,0x00,0x01,0x21,0x21,0x21,0x3f,0x21,0x2f};
uchar code TABLE4[]={0x44,0x24,0xfc,0x00,0x00,0xfe,0x04,0x00,0x00,0x08,0x14,0x04,0x04,0xfc,0x04,0xf4};
uchar code TABLE5[]={0x22,0x24,0x3F,0x02,0x01,0x7f,0x01,0x01,0x00,0x01,0x01,0x21,0x21,0x3f,0x21,0x2f};
uchar code TABLE6[]={0x44,0x24,0xfc,0x00,0x00,0xfe,0x04,0x00,0x00,0x08,0x14,0x04,0x04,0xfc,0x04,0xf4};
uchar code TABLE7[]={0x22,0x24,0x3F,0x02,0x01,0x7f,0x01,0x01,0x00,0x01,0x01,0x01,0x21,0x3f,0x21,0x2f};
uchar code TABLE8[]={0x44,0x24,0xfc,0x00,0x00,0xfe,0x04,0x00,0x00,0x08,0x14,0x04,0x04,0xfc,0x04,0xf4};

void main()
{
   uchar  i;
   uchar   j;
   uchar   k;       
   bit   flag1;
   bit   flag2;
   //bit   flag3;
   //bit   flag4;
   uchar digit1; 
   uchar digit2; 
   for(; ;)
   {
     digit1=0x01;	  
     flag1=0;	  	      
     fro(k=0;k<80;k++)  
	 {    	
       for(i=0;i<16;i++)
       {
 		DATBIT1=0;
		DATBIT2=0;
		DATBIT3=0;
		DATBIT4=0;
	    if(digit1 ==0x00)  digit1=0x01;	
		j=k/20;
        switch(j)
  		{
		   case 3:
		   {		 						     
     	   DAT1=TABLE7[i];
           DAT2=TABLE8[i];
		   DAT3=TABLE5[i];
           DAT4=TABLE6[i];
           DAT5=TABLE3[i];
           DAT6=TABLE4[i];
           DAT7=TABLE1[i];
           DAT8=TABLE2[i];
		   } break;
           case 2:
		  {
           DAT1=TABLE5[i];
           DAT2=TABLE6[i];
		   DAT3=TABLE3[i];
           DAT4=TABLE4[i];
           DAT5=TABLE1[i];
           DAT6=TABLE2[i];
		   } break;
		   case 1:
		   {
		   DAT1=TABLE3[i];
           DAT2=TABLE4[i];
		   DAT3=TABLE1[i];
           DAT4=TABLE2[i];
		   } break;
		  default:
		  {
		   DAT1=TABLE1[i];
           DAT2=TABLE2[i];
		   }
          }
          if(flag1==1)           DATBIT2=digit1;  
          else                   DATBIT1=digit1;   
		  for(j=0;j<200;j++);
		  if(digit1 ==0x80)      flag1=!flag1;
          digit1<<=1;		   
   		 
      }	
	}	       
   }
}