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📄 interconn.iml

📁 利用CANDANCE软件做的一个板级信号完整性分析的例子
💻 IML
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("interconn.iml"  (Trace   (STL_1S_1R_1    (IDL ".subckt STL_1S_1R_1 +X1 0+X2 0*EMIinfo Type Top MicroStrip*EMIinfo Conductor Width=5 botDist=0.0002032*EMIinfo Dielectric Eps=4.5 Thick=0.0002032*EMIinfo Plane Z=0.00049784.layerstack Layerstack3+shield( 3.048e-005 1 0 )+dielectric( 0.0002032 4.5 0 ).crosssection+rectangle ( 5.959e+007 0 0.0002032 0.000127 0.00023368 )+Length=length.rlgc RLGCSTL_1S_1R_1 ( Length=length N=1 ).C 0+ 7.024000e-011 .L 0+ 4.626200e-007 .G 0+ 0.000000e+000 .R 0+ 4.335200e+000 .endrlgc RLGCSTL_1S_1R_1**The Characteristic Modal Delay, Admittance and**Impedance Matrices of these Transmission Lines:*Delay Matrix.*Td 0 (n=1)*  5.700400e-009 *Admittance Matrix.*Y 0 (n=1)* 1.232200e-002 *Impedance Matrix.*Z 0 (n=1)*  8.115600e+001 **The Near-End Crosstalk Coefficent of these Transmission**Lines based on Near-End Resistance=50 ohm assumption:*Near-End Crosstalk Coefficent Matrix, Z0*Inv(R+Z0).*  0 (n=1)*  6.187700e-001 .ends STL_1S_1R_1" )    (KSPICE "DATAPOINTS RLGC STL_1S_1R_1FREQUENCY=0CMATRIX 7.024000e-011LMATRIX 4.626200e-007GMATRIX 0.000000e+000RMATRIX 4.335200e+000END RLGC" )    (Frequency 0 ) )   (STL_1S_1R_2    (IDL ".subckt STL_1S_1R_2 +X1 0+X2 0*EMIinfo Type Bottom MicroStrip*EMIinfo Plane Z=0.00023368*EMIinfo Dielectric Eps=4.5 Thick=0.0002032*EMIinfo Conductor Width=5 topDist=0.0002032.layerstack Layerstack1+dielectric( 0.0002032 4.5 0 )+shield( 3.048e-005 1 0 ).crosssection+rectangle ( 5.959e+007 0 -3.048e-005 0.000127 0 )+Length=length.rlgc RLGCSTL_1S_1R_2 ( Length=length N=1 ).C 0+ 7.024000e-011 .L 0+ 4.626200e-007 .G 0+ 0.000000e+000 .R 0+ 4.335200e+000 .endrlgc RLGCSTL_1S_1R_2**The Characteristic Modal Delay, Admittance and**Impedance Matrices of these Transmission Lines:*Delay Matrix.*Td 0 (n=1)*  5.700400e-009 *Admittance Matrix.*Y 0 (n=1)* 1.232200e-002 *Impedance Matrix.*Z 0 (n=1)*  8.115600e+001 **The Near-End Crosstalk Coefficent of these Transmission**Lines based on Near-End Resistance=50 ohm assumption:*Near-End Crosstalk Coefficent Matrix, Z0*Inv(R+Z0).*  0 (n=1)*  6.187700e-001 .ends STL_1S_1R_2" )    (KSPICE "DATAPOINTS RLGC STL_1S_1R_2FREQUENCY=0CMATRIX 7.024000e-011LMATRIX 4.626200e-007GMATRIX 0.000000e+000RMATRIX 4.335200e+000END RLGC" )    (Frequency 0 ) )   (STL_1S_1R_3    (IDL ".subckt STL_1S_1R_3 +X1 0+X2 0*EMIinfo Type Top MicroStrip*EMIinfo Conductor Width=5 botDist=0.000127*EMIinfo Dielectric Eps=4.5 Thick=0.000127*EMIinfo Plane Z=0.00049784.layerstack Layerstack3+shield( 3.048e-005 1 0 )+dielectric( 0.000127 4.5 0 ).crosssection+rectangle ( 5.959e+007 0 0.000127 0.000127 0.00015748 )+Length=length.rlgc RLGCSTL_1S_1R_3 ( Length=length N=1 ).C 0+ 8.751300e-011 .L 0+ 3.786300e-007 .G 0+ 0.000000e+000 .R 0+ 4.335200e+000 .endrlgc RLGCSTL_1S_1R_3**The Characteristic Modal Delay, Admittance and**Impedance Matrices of these Transmission Lines:*Delay Matrix.*Td 0 (n=1)*  5.756300e-009 *Admittance Matrix.*Y 0 (n=1)* 1.520300e-002 *Impedance Matrix.*Z 0 (n=1)*  6.577700e+001 **The Near-End Crosstalk Coefficent of these Transmission**Lines based on Near-End Resistance=50 ohm assumption:*Near-End Crosstalk Coefficent Matrix, Z0*Inv(R+Z0).*  0 (n=1)*  5.681300e-001 .ends STL_1S_1R_3" )    (KSPICE "DATAPOINTS RLGC STL_1S_1R_3FREQUENCY=0CMATRIX 8.751300e-011LMATRIX 3.786300e-007GMATRIX 0.000000e+000RMATRIX 4.335200e+000END RLGC" )    (Frequency 0 ) )   (STL_1S_1R_6    (IDL ".subckt STL_1S_1R_6 +X1 0+X2 0*EMIinfo Type Bottom MicroStrip*EMIinfo Plane Z=0.00015748*EMIinfo Dielectric Eps=4.5 Thick=0.000127*EMIinfo Conductor Width=5 topDist=0.000127.layerstack Layerstack1+dielectric( 0.000127 4.5 0 )+shield( 3.048e-005 1 0 ).crosssection+rectangle ( 5.959e+007 0 -3.048e-005 0.000127 0 )+Length=length.rlgc RLGCSTL_1S_1R_6 ( Length=length N=1 ).C 0+ 8.751300e-011 .L 0+ 3.786300e-007 .G 0+ 0.000000e+000 .R 0+ 4.335200e+000 .endrlgc RLGCSTL_1S_1R_6**The Characteristic Modal Delay, Admittance and**Impedance Matrices of these Transmission Lines:*Delay Matrix.*Td 0 (n=1)*  5.756300e-009 *Admittance Matrix.*Y 0 (n=1)* 1.520300e-002 *Impedance Matrix.*Z 0 (n=1)*  6.577700e+001 **The Near-End Crosstalk Coefficent of these Transmission**Lines based on Near-End Resistance=50 ohm assumption:*Near-End Crosstalk Coefficent Matrix, Z0*Inv(R+Z0).*  0 (n=1)*  5.681300e-001 .ends STL_1S_1R_6" )    (KSPICE "DATAPOINTS RLGC STL_1S_1R_6FREQUENCY=0CMATRIX 8.751300e-011LMATRIX 3.786300e-007GMATRIX 0.000000e+000RMATRIX 4.335200e+000END RLGC" )    (Frequency 0 ) ) )  (LibraryVersion 136.2 ) ) 

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