eight2ten.cpp

八进制转化为二进制的C++实现方法

//=====================================
// title: 八进制转换为十进制
// author: cjj
// date: 2007-10-08
/* Description: 

*/
//=====================================
#include <iostream>
#include <cmath>
#include <vector>
using namespace std;

int main()
{
	for (int num; cin >> num;)
	{
		//求出位数
		int bitNum = 1, temp = 1;
		while (temp < num)
		{
			bitNum++;
			temp *= 8;
		}
		bitNum = bitNum - 1;

		//提取每一位数，并与相应的8的次方数相乘，求出总和sum
		int sum = 0;
		for (int i = 0; i < bitNum; i++)
		{
			sum = sum + (num % 10) * (int) pow(8, i);
			num /= 10;
		}
		cout << sum << endl;
	}
	return 0;
}