testch10.m

来自「市面上电力系统的范例 直得收藏学习的ㄧ本书」· M 代码 · 共 25 行

Vabc=[100    0
      100  -120
      100   115];
Zabc =[5+j*8.66     j*0     j*0
          j*0  5+j*8.66     j*0
         j*0      j*0  5+j*8.66];
Z012 = zabc2sc(Zabc)          % Symmetrical components of impedance
V012 = abc2sc(Vabc);            % Symmetrical components of voltage
V012p= rec2pol(V012)  % Converts rectangular phasors to polar forms
%I012 =[0 0
 %   9.99 -61.7
  %  0.29  87.5]           % Symmetrical components of current
I012p= rec2pol(I012)  % Converts rectangular phasors to polar forms
Iabc = sc2abc(I012);                               % Phase currents
Iabcp= rec2pol(Iabc)  % Converts rectangular phasors to polar forms
%S3ph = 3*(V012.')*conj(I012)  %  Power using symmetrical components
%Vabcr = Vabc(:,1).*(cos(pi/180*Vabc(:,2))+j*sin(pi/180*Vabc(:,2)));
%S3ph=(Vabcr.')*conj(Iabc) % Power using phase currents and voltages

I012 =[0.177 -39.3
   9.99 -61.7
   0.29  87.5] 
%I012p= rec2pol(I012)  % Converts rectangular phasors to polar forms
Iabc = sc2abc(I012);                               % Phase currents
Iabcp= rec2pol(Iabc)  % Converts rectangular phasors to polar forms