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📄 彻底研究正则表达式 __.htm

📁 正则表达式的应用
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       System.out.println(m18.find());
       
       <FONT color=#0d00e0>//test CANON_EQ这个是jdk的例子但我实在不明白是什么意思,向大家请教</FONT>
       System.out.println(<FONT color=#00ed0>"test CANON_EQ"</FONT>);
       Pattern p19=Pattern.compile(<FONT color=#00ed0>"a\u030A"</FONT>,Pattern.CANON_EQ);
       System.out.println(Character.getType(<FONT color=#00a000>'\u030A'</FONT>));
       System.out.println(<FONT color=#00ed0>"is"</FONT>+Character.isISOControl(<FONT color=#00a000>'\u030A'</FONT>));
       System.out.println(<FONT color=#00ed0>"is"</FONT>+Character.isUnicodeIdentifierPart(<FONT color=#00a000>'\u030A'</FONT>));
       System.out.println(Character.getType(<FONT color=#00a000>'\u00E5'</FONT>));
       System.out.println(<FONT color=#00ed0>"is"</FONT>+Character.isISOControl(<FONT color=#00a000>'\u00E5'</FONT>));
       Matcher m19=p19.matcher(<FONT color=#00ed0>"\u00E5"</FONT>);
       System.out.println(m19.matches());
       System.out.println(Character.getType(<FONT color=#00a000>'\u0085'</FONT>));
       System.out.println(<FONT color=#00ed0>"is"</FONT>+Character.isISOControl(<FONT color=#00a000>'\u0085'</FONT>));
&nbsp;
      <FONT color=#0d00e0>//注意下面三个例子体会Greedy,Reluctant and Possessive Quantifiers的不同</FONT>
       Pattern ppp=Pattern.compile(<FONT color=#00ed0>".*foo"</FONT>);
       Matcher mmm=ppp.matcher(<FONT color=#00ed0>"xfooxxxxxxfoo"</FONT>);
       <FONT color=#0d00e0>/**
        * Greedy   quantifiers 
           X?      X, once or not at all 
           X*      X, zero or more times 
           X+      X, one or more times 
           X{n}    X, exactly n times 
           X(n,}   X, at least n times 
           X{n,m}  X, at least n but not more than m times 
           Greedy quantifiers是最常用的一种,如上,它的匹配方式是先匹配尽可能多的字符,当
           这样造成整个表达式整体不能匹配时就退一个字符再试比如:
           .*foo与xfooxxxxxxfoo的匹配过程,.*先与整个输入匹配,发现这样不行,整个串不能匹配
        *  于是退最后一个字符"o"再试,还不行,再退直到把foo都退出才发现匹配于是结束。因为这个过程
        *  总是先从最大匹配开始到找到一个匹配,所以.*与之匹配的总是一个最大的,这个特点和资本家相似
        *  故名贪婪的
        */</FONT>
       <FONT color=#00a000><B>boolean</B></FONT> isEnd=<FONT color=#00a000><B>false</B></FONT>;
       <FONT color=#00a000><B>int</B></FONT> k=0;
       System.out.println(<FONT color=#00ed0>"=========="</FONT>);
       System.out.println(<FONT color=#00ed0>"xfooxxxxxxfoo"</FONT>);
       <FONT color=#00a000><B>while</B></FONT>(isEnd==<FONT color=#00a000><B>false</B></FONT>)
       <FONT color=#00a000><B>try</B></FONT><FONT color=#00a000>{</FONT>
           System.out.println(<FONT color=#00ed0>"the:"</FONT>+k++);
           System.out.println(mmm.find());
           System.out.println(mmm.end());
       <FONT color=#00a000>}</FONT><FONT color=#00a000><B>catch</B></FONT>(Exception e)<FONT color=#00a000>{</FONT>
           isEnd=<FONT color=#00a000><B>true</B></FONT>;
       <FONT color=#00a000>}</FONT>
       isEnd=<FONT color=#00a000><B>false</B></FONT>;
       Pattern ppp1=Pattern.compile(<FONT color=#00ed0>".*?foo"</FONT>);
       Matcher mmm1=ppp1.matcher(<FONT color=#00ed0>"xfooxxxxxxfoo"</FONT>);
       <FONT color=#0d00e0>/**
        * Reluctant quantifiers 
           X??       X, once or not at all 
           X*?       X, zero or more times 
           X+?       X, one or more times 
           X{n}?     X, exactly n times 
           X(n,}?    X, at least n times 
           X{n,m}?   X, at least n but not more than m times 
           Reluctant quantifiers的匹配方式正好相反,它总是先从最小匹配开始,如果这时导致
           整个串匹配失败则再吃进一个字符再试,如:
           .*?foo与xfooxxxxxxfoo的匹配过程,首先,.*与空串匹配,这时整个串匹配失败,于是
        *  再吃一个x,这时发现整个串匹配成功,当再调用find时从上次匹配结束时开始找,先吃一个
        *  空串,不行,再吃一个x,不行,……直到把中间所有x都吃掉才发现匹配成功。这种方式总
        *  是从最小匹配开始所以它能找到最多次数的匹配,但第一匹配都是最小的。它的行为有点象雇佣
        *  工人,总是尽可能少的于活,故名勉强的。
        */</FONT>
       k=0;
       System.out.println(<FONT color=#00ed0>"?????????????????????"</FONT>);
       System.out.println(<FONT color=#00ed0>"xfooxxxxxxfoo"</FONT>);
       <FONT color=#00a000><B>while</B></FONT>(isEnd==<FONT color=#00a000><B>false</B></FONT>)
       <FONT color=#00a000><B>try</B></FONT><FONT color=#00a000>{</FONT>
           System.out.println(<FONT color=#00ed0>"the:"</FONT>+k++);
           System.out.println(mmm1.find());
           System.out.println(mmm1.end());
       <FONT color=#00a000>}</FONT><FONT color=#00a000><B>catch</B></FONT>(Exception e)<FONT color=#00a000>{</FONT>
           isEnd=<FONT color=#00a000><B>true</B></FONT>;
       <FONT color=#00a000>}</FONT>
       isEnd=<FONT color=#00a000><B>false</B></FONT>;
       Pattern pp2=Pattern.compile(<FONT color=#00ed0>".*+foo"</FONT>);
       Matcher mm2=pp2.matcher(<FONT color=#00ed0>"xfooxxxxxxfoo"</FONT>);
       <FONT color=#0d00e0>/**
        * 
           Possessive quantifiers 
           X?+        X, once or not at all 
           X*+        X, zero or more times 
           X++        X, one or more times 
           X{n}+      X, exactly n times 
           X(n,}+     X, at least n times 
           X{n,m}+    X, at least n but not more than m times 
           Possessive quantifiers 这种匹配方式与Greedy方式相似,所不同的是它不够聪明,当
           它一口吃掉所有可以吃的字符时发现不匹配则认为整个串都不匹配,它不会试着吐出几个。它的行
           为和大地主相似,贪婪但是愚蠢,所以名曰强占的。
        */</FONT>
&nbsp;
       <FONT color=#00a000><B>int</B></FONT> ii=0;
       System.out.println(<FONT color=#00ed0>"+++++++++++++++++++++++++++"</FONT>);
       System.out.println(<FONT color=#00ed0>"xfooxxxxxxfoo"</FONT>);
       <FONT color=#00a000><B>while</B></FONT>(isEnd==<FONT color=#00a000><B>false</B></FONT>)
       <FONT color=#00a000><B>try</B></FONT><FONT color=#00a000>{</FONT>
           System.out.println(<FONT color=#00ed0>"the:"</FONT>+ii++);
           System.out.println(mm2.find());
           System.out.println(mm2.end());
       <FONT color=#00a000>}</FONT><FONT color=#00a000><B>catch</B></FONT>(Exception e)<FONT color=#00a000>{</FONT>
           isEnd=<FONT color=#00a000><B>true</B></FONT>;
       <FONT color=#00a000>}</FONT>
&nbsp;
&nbsp;
   <FONT color=#00a000>}</FONT>
&nbsp;
<FONT color=#00a000>}</FONT>
&nbsp;
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                <TD width="97%"><SPAN class=jive-subject><A 
                  name=148349></A>彻底研究正则表达式 </SPAN><BR><SPAN 
                  class=jive-description>发表于: 2003-12-1 上午4:01 &nbsp; <NOBR><A 
                  title="原帖: netlogic" 
                  href="http://bbs.chinajavaworld.com/message.jspa?messageID=148348#148348"><IMG 
                  height=10 alt="" src="彻底研究正则表达式%20___files/up-10x10.gif" 
                  width=10 border=0></A> 原帖: <A title=到该帖子 
                  href="http://bbs.chinajavaworld.com/message.jspa?messageID=148348#148348">netlogic</A> 
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                  <BLOCKQUOTE><FONT color=#666666><B>引用原文:</B></FONT>
                    <HR noShade SIZE=1>
                    <FONT color=#339999><STRONG>下面引用由 <U>netlogic </U>在 
                    <I>2003/11/29 11:11pm</I> 发表的内容:</STRONG> &nbsp;//test 
                    CANON_EQ这个是jdk的例子但我实在不明白是什么意思,向大家请教 &nbsp; &nbsp; &nbsp; 
                    System.out.println("test CANON_EQ"); &nbsp; &nbsp; &nbsp; 
                    Pattern p19=Pattern.compile("a\u030A",Pattern.CANON_EQ); 

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