📄 erweishuangqu.m
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function [s1,s2,s3]=erweishuangqu(f,a,b,c,h,t,s0)
%s1,s2,s3分别是数值解,精确解和误差在指定节点上的值,f,a,b是与方程有关的函数,h,t分别是空间和时间步长,s0则是精确解
s=t/h;
m=1/h;
n=1/t;
for i=1:m+1
x(i)=(i-1)*h;
y(i)=(i-1)*h;
end
for k=1:n+1
z(k)=(k-1)*t;
end
for i=1:m+1
for j=1:m+1
u(i,j,1)=a(x(i),y(j));
u(i,j,2)=a(x(i),y(j))+t*b(x(i),y(j))+(t*t)/2*f(x(i),y(j),0);
end
end
for k=3:2:n+1
for j=1:m+1
u(1,j,k)=c(x(1),y(j),z(k));
u(m+1,j,k)=c(x(m+1),y(j),z(k));
end
for i=2:m
u(i,1,k)=c(x(i),y(1),z(k));
u(i,m+1,k)=c(x(i),y(m+1),z(k));
end
end
for k=4:2:n+1
for j=2:m
u(1,j,k)=c(x(1),y(j),z(k))+u(1,j,2)-c(x(1),y(j),z(2));
u(m+1,j,k)=c(x(m+1),y(j),z(k))+u(m+1,j,2)-c(x(m+1),y(j),z(2));
end
for i=2:m
u(i,1,k)=c(x(i),y(1),z(k))+u(i,1,2)-c(x(i),y(1),z(2));
u(i,m+1,k)=c(x(i),y(m+1),z(k))+u(i,m+1,2)-c(x(i),y(m+1),z(2));
end
end
w1=ones(1,m-1);w2=ones(1,m-2);
A1=diag(w1);A2=diag(w2,-1);A3=diag(w2,1);
A=(1+s*s)*A1-s*s/2*A2-s*s/2*A3;
B=-4/(h*h)*A1+1/(h*h)*A2+1/(h*h)*A3;
for k=2:n
for j=2:m
v1(1,j-1)=-s*s/(2*t*t)*(u(1,j-1,k-1)+u(1,j+1,k-1)-2*u(1,j-1,k)-2*u(1,j+1,k)+u(1,j-1,k+1)+u(1,j+1,k+1))+(1+s*s)/(t*t)*(u(1,j,k-1)-2*u(1,j,k)+u(1,j,k+1));
v1(m+1,j-1)=-s*s/(2*t*t)*(u(m+1,j-1,k-1)+u(m+1,j+1,k-1)-2*u(m+1,j-1,k)-2*u(m+1,j+1,k)+u(m+1,j-1,k+1)+u(m+1,j+1,k+1))+(1+s*s)/(t*t)*(u(m+1,j,k-1)-2*u(m+1,j,k)+u(m+1,j,k+1));
for i=1:m-1
d1(i)=u(i+1,j,k);
end
d2(1)=1/(h*h)*(u(2,j-1,k)+u(2,j+1,k)+u(1,j,k))+f(x(2),y(j),z(k))+s*s/2*v1(1,j-1);
d2(m-1)=1/(h*h)*(u(m,j-1,k)+u(m,j+1,k)+u(m+1,j,k))+f(x(m),y(j),z(k))+s*s/2*v1(m,j-1);
for i=2:m-2
d2(i)=(u(i+1,j-1,k)+u(i+1,j+1,k))/(h*h)+f(x(i+1),y(j),z(k));
end
d=B*d1'+d2';
v=chase(A,d,m-2);
for i=2:m
v1(i,j-1)=v(i-1);
end
end
for i=2:m
u1(i-1,1)=(u(i,1,k-1)-2*u(i,1,k)+u(i,1,k+1))/(t*t);
u1(i-1,m+1)=(u(i,m+1,k-1)-2*u(i,m+1,k)+u(i,m+1,k+1))/(t*t);
d(1)=v1(i,1)+(s*s)/2*u1(i-1,1);
d(m-1)=v1(i,m-1)+(s*s)/2*u1(i-1,m+1);
for j=2:m-2
d(j)=v1(i,j);
end
v=chase(A,d,m-2);
for j=2:m
u1(i-1,j)=v(j-1);
end
end
for i=2:m
for j=2:m
u(i,j,k+1)=(t*t)*u1(i-1,j)+2*u(i,j,k)-u(i,j,k-1);
end
end
end
for i=1:m+1
for j=1:m+1
for k=1:n+1
u0(i,j,k)=s0(x(i),y(j),z(k));
end
end
end
E=u-u0;
s1=single(u(21,21,5:4:41));
s2=single(u0(21,21,5:4:41));
s3=single(abs(E(21,21,5:4:41)));
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