📄 y_bus.m
字号:
% change the bus no. to the connective integer no.
% remark: let bus 1 is swing bus, bus 2~ ngen+1 is PV bus, bus ngen+2~nbus is PQ bus
a=busdata(:,1); kb=busdata(:,2); c=[linedata(:,1), linedata(:,2)];
nbus=length(a); nbr=size(c,1);
%busdata(:,1)=sort(randperm(nbus))';
%for i=1:nbus
% Index=find(c==a(i));
% linedata(Index)=i;
%end
% This program obtains th Bus Admittance Matrix for power flow solution
j=sqrt(-1);
nl = linedata(:,1); nr = linedata(:,2); R = linedata(:,3);
X = linedata(:,4); Bc = j*(linedata(:,5))/2; a = linedata(:,6);
Index = find( a<= 0); a(Index) = 1;
y= ones(nbr,1)./(R + j*X); %branch admittance
Ybus=zeros(nbus,nbus);
for k=1:nbr;
nlk = nl(k); nrk = nr(k);
Ybus(nlk,nrk) = Ybus(nlk,nrk) - y(k)/a(k);
Ybus(nrk,nlk) = Ybus(nlk,nrk);
Ybus(nlk,nlk) = Ybus(nlk,nlk) + y(k)/(a(k)^2) + Bc(k);
Ybus(nrk,nrk) = Ybus(nrk,nrk) + y(k) + Bc(k);
end
⌨️ 快捷键说明
复制代码
Ctrl + C
搜索代码
Ctrl + F
全屏模式
F11
切换主题
Ctrl + Shift + D
显示快捷键
?
增大字号
Ctrl + =
减小字号
Ctrl + -