纸牌游戏问题.txt

用C++实现的制作一个简单的纸牌游戏的程序源码,大家可能在做报告时遇到

#include <stdio.h> 
#include <math.h> 
#include <stdlib.h> 
#include <dos.h> 
#include <graphics.h> 
#include <conio.h> 
#define ESC 0x1b 

struct card 
{ 
char color; 
int number; 
int signin; 
}a[52]={{3,2,1},{3,3,1},{3,4,1},{3,5,1},{3,6,1},{3,7,1},{3,8,1},{3,9,1},{3,10,1},{3,74,1},{3,81,1},{3,75,1},{3,65,1}, 
{4,2,1},{4,3,1},{4,4,1},{4,5,1},{4,6,1},{4,7,1},{4,8,1},{4,9,1},{4,10,1},{4,74,1},{4,81,1},{4,75,1},{4,65,1}, 
{5,2,1},{5,3,1},{5,4,1},{5,5,1},{5,6,1},{5,7,1},{5,8,1},{5,9,1},{5,10,1},{5,74,1},{5,81,1},{5,75,1},{5,65,1}, 
{6,2,1},{6,3,1},{6,4,1},{6,5,1},{6,6,1},{6,7,1},{6,8,1},{6,9,1},{6,10,1},{6,74,1},{6,81,1},{6,75,1},{6,65,1}},b[52]; 
char s[10]; 
int d[52]; 

fan(int n) 
{ 
if(a[n].signin==0) 
a[n].signin=1; 
else a[n].signin=0; 
return; 
} 

suiji() 
{ 
int t=0,j,i=0,struction; 
for(i=0;i<=51;i++) 
d[i]=-1; 
i=0; 
randomize(); 
while(i<52) 
{ 
struction=random(52); 
for(j=0;j<i;j++) 
{ 
if(d[j]==struction) 
{ 
t=1; 
break; 
} 
} 
if(t==0) 
{ 
d[i]=struction; 
i++; 
} 
else t=0; 
} 
return; 
} 


card(int n) 
{ 
int y,x=n%13,x1=d[n]%13,y1; 
char s1[2],r[2]; 
y=(n-x)/13; 
setcolor(15); 
line(49*x,80*y+42,49*x,80*y+117); 
line(49*x+47,80*y+42,49*x+47,80*y+117); 
line(49*x,80*y+42,49*x+47,80*y+42); 
line(49*x,80*y+117,49*x+47,80*y+117); 
for(y1=1;y1<75;y1++) 
{ 
setcolor(15); 
line(49*x+1,80*y+y1+42,49*x+45,80*y+y1+42); 
} 
if(a[n].signin==1) 
{ 
setcolor(1); 
if(a[d[n]].color==3||a[d[n]].color==4) 
setcolor(RED); 
sprintf(s1,"%c",a[d[n]].color); 
outtextxy(49*x+3,80*y+45,s1); 
if(x1<9) 
sprintf(r,"%d",a[d[n]].number); 
else sprintf(r,"%c",a[d[n]].number); 
outtextxy(49*x+3,80*y+54,r); 
} 
else against(n); 
setcolor(WHITE); 
return; 
} 

against(int n) 
{ 
int y,y1,x=n%13; 
y=(n-x)/13; 
for(y1=1;y1<75;y1++) 
{ 
setcolor(BLUE); 
line(49*x+1,80*y+y1+42,49*x+45,80*y+y1+42); 
} 
setcolor(15); 
return; 
} 

draw(int n,int m) 
{ 
int i4; 
setcolor(YELLOW); 
sprintf(s,"Base: %d",n); 
outtextxy(150,420,s); 
if(d[m-1]%13<9&&d[m-1]%13>=0) 
sprintf(s,"Card: %c %d",a[d[m-1]].color,a[d[m-1]].number); 
else sprintf(s,"Card: %c %c",a[d[m-1]].color,a[d[m-1]].number); 
outtextxy(150,430,s); 
setcolor(15); 
for(i4=0;i4<52;i4++) 
{ 
card(i4); 
} 
return; 
} 

frame(int n) 
{ 
int y,x=n%13; 
y=(n-x)/13; 
setcolor(RED); 
line(49*x,80*y+42,49*x,80*y+117); 
line(49*x+47,80*y+42,49*x+47,80*y+117); 
line(49*x,80*y+42,49*x+47,80*y+42); 
line(49*x,80*y+117,49*x+47,80*y+117); 
setcolor(15); 
return; 
} 



huatu(int i,int j) 
{ 
int n,m,i1=i,b,b2,j1=j,sign=0,tar=0,i2=2,k=1,p,sign1=0; 
char u='',u1='',c[7][8],chh; 

setbkcolor(3); 
while(1) 
{ 
loop: 
sprintf(c[0],"File"); 
sprintf(c[1],"Option"); 
sprintf(c[2],"Help"); 
sprintf(c[3],"New"); 
sprintf(c[4],"Exit"); 
sprintf(c[5],"Auto"); 
sprintf(c[6],"Manual"); 

while(i2<=52) 
{ 

k=1; 
while(i2*k<=52) 
{ 
setcolor(9); 
for(n=0;n<=18;n++) 
line(0,n,639,n); 
setcolor(15); 
outtextxy(290,10,"Card Game"); 
setcolor(YELLOW); 
for(n=19;n<=40;n++) 
line(0,n,639,n); 
for(m=0;m<=2;m++) 
{ 
setcolor(0); 
line(58*m+3,22,58*m+3,38); 
line(58*m+3,38,58*m+58,38); 
line(58*m+58,22,58*m+58,38); 
line(58*m+3,22,58*m+58,22); 
outtextxy(8+58*m,27,c[m]); 
if(m==i1) 
{ 
setcolor(0); 
for(n=0;n<=16;n++) 
line(58*m+3,22+n,58*m+58,22+n); 
setcolor(YELLOW); 
outtextxy(8+58*m,27,c[m]); 
} 
if(kbhit()) 
{ 
chh=getch(); 
if(chh==0x1b) 
{ 
u=''; 
u1=''; 
goto loop; 
} 
} 
} 

if(u!='N') 
{ 
sign1=1; 
break; 
} 
if(u=='N') 
{ 
if(u1!='A'&&u1!='M') 
{ 
p=i2*k; 
draw(i2,p); 
sign1=1; 
break; 
} 
if(u1=='A'||u1=='M') 
{ 
p=i2*k; 
draw(i2,p); 
sign1=0; 
fan(i2*k-1); 
frame(i2*k-1); 
if(u1=='M') 
{ 
outtextxy(150,440,"Press any key to continue!"); 
getch(); 
} 
cleardevice(); 
k++; 
} 
} 
} 
if(sign1==1)break; 
i2++; 
} 
if(i2>=52) 
{ 
setcolor(9); 
for(n=0;n<=18;n++) 
line(0,n,639,n); 
setcolor(15); 
outtextxy(290,10,"Card Game"); 
setcolor(YELLOW); 
for(n=19;n<=40;n++) 
line(0,n,639,n); 
outtextxy(150,420,"Press any key to continue!"); 

for(m=0;m<=2;m++) 
{ 
setcolor(0); 
line(58*m+3,22,58*m+3,38); 
line(58*m+3,38,58*m+58,38); 
line(58*m+58,22,58*m+58,38); 
line(58*m+3,22,58*m+58,22); 
outtextxy(8+58*m,27,c[m]); 
if(m==i1) 
{ 
for(n=0;n<=16;n++) 
line(58*m+3,22+n,58*m+58,22+n); 
setcolor(YELLOW); 
outtextxy(8+58*m,27,c[m]); 
} 
} /*打印一级菜单*/ 

getch(); 
cleardevice(); 
setcolor(9); 
for(n=0;n<=18;n++) 
line(0,n,639,n); 
setcolor(15); 
outtextxy(290,10,"Card Game"); 
setcolor(YELLOW); 
for(n=19;n<=40;n++) 
line(0,n,639,n); 
for(m=0;m<=2;m++) 
{ 
setcolor(0); 
line(58*m+3,22,58*m+3,38); 
line(58*m+3,38,58*m+58,38); 
line(58*m+58,22,58*m+58,38); 
line(58*m+3,22,58*m+58,22); 
if(m==i1) 
{ 
for(n=0;n<=16;n++) 
line(58*m+3,22+n,58*m+58,22+n); 
setcolor(YELLOW); 
} 
outtextxy(8+58*m,27,c[m]); 
} 

draw(52,52); 

} 
if(u1=='M'||u1=='A') 
{ 
u1=''; 
u=''; 
} 

b=getch(); 

while(1) 
{ 
if(b==100) 
{ 
i1=(i1+1)%3; 
break; 
} 
if(b==97) 
{ 
if(i1==0) 
{ 
i1=2; 
break; 
} 
else 
{ 
i1=i1-1; 
break; 
} 
} 
/* if(b==0x1b) 
{ 
closegraph(); 
exit(1); 
} */ 
if(b==13) 
{ 
while(1) 
{ 

if(i1!=2) 
{ 
if(sign!=1) 
{ 

setcolor(YELLOW); 
for(m=1;m<=2;m++) 
{ 
line(58*i1+3,38+15*(m-1),58*i1+3,53+15*(m-1)); 
line(58*i1+3,53+15*(m-1),58*i1+58,53+15*(m-1)); 
line(58*i1+58,38+15*(m-1),58*i1+58,53+15*(m-1)); 
line(58*i1+3,38+15*(m-1),58*i1+58,38+15*(m-1)); 
setcolor(3); 
for(n=0;n<=13;n++) 
{ 
line(58*i1+4,39+15*(m-1)+n,58*i1+57,39+15*(m-1)+n); 
} 
if(m==j1+1) 
{ 
setcolor(3); 
for(n=0;n<=13;n++) 
{ 
line(58*i1+4,39+15*(tar)+n,58*i1+57,39+15*(tar)+n); 
} 
setcolor(BLUE); 
for(n=0;n<=13;n++) 
{ 
line(58*i1+4,39+15*(j1)+n,58*i1+57,39+15*(j1)+n); 
} 
tar=j1; 

} 
setcolor(YELLOW); 
} 

setcolor(YELLOW); 
if(i1==0) 
{ 
outtextxy(8+58*i1,43,c[i1+3]); 
outtextxy(8+58*i1,58,c[i1+4]); 
} 
else 
{ 
outtextxy(8+58*i1,43,c[i1+4]); 
outtextxy(8+58*i1,58,c[i1+5]); 
} 
} 
if(sign==1)break; 
setcolor(YELLOW); 

while(1) 
{ 
b2=getch(); 
if(b2==115) 
{ 
j1=(j1+1)%2; 
break; 
} 

if(b2==119) 
{ 
if(j1==1) 
{ 
j1=0; break; 
} 
if(j1==0) 
{ 
j1=1; break; 
} 
} 

if(b2==0x1b) 
{ 
sign=1; 
j1=0; 
break; 
} 
if(b2==13) 
{ 
if(i1==0&&j1==1) 
{ 
closegraph(); 
exit(1); 
} 
if(i1==0&&j1==0) 
{ 
u='N'; 
suiji(); 
for(n=0;n<52;n++) 
{ 
a[n].signin=1; 
} 
n=0; 
} 
if(i1==1&&j1==0) 
{ 
u1='A'; 
if(u!='N') u1=''; 
} 
if(i1==1&&j1==1) 
{ 
u1='M'; 
if(u!='N') u1=''; 
} 
sign=1; 
j1=0; 
break; 
} 
else continue; 
} 
} 
else 
{ 
sign=1; 
outtextxy(100,100,"Copyright"); 
circle(180,104,5); 
outtextxy(177,101,"C"); 
getch(); 
break; 
} 



} 
} 
else break; 
if(sign==1) 
{ 
sign=0; 
break; 
} 
} 
cleardevice(); 
i2=2; 
k=1; 

} 
} 

main() 
{ 
int k,gm=2,gd=9; 

initgraph(&gd,&gm,""); 
huatu(0,0); 
getch(); 
} 
回答者：whoam1 - 助理 三级 7-10 23:09

#include <stdio.h> 

main() 
{ 
int arr[53],i,k,j ; 
k=2 ; 
for(i=1;i<=52;i++) 
arr[i]=i ; 
for(i=2;i<=52;i++) 
{ 
for(j=k;j<=52;j++) 
{ 
if(j%k==0) 
{ 
if(arr[j]==0) 
arr[j]=j ; 
else arr[j]=0 ; 
} 
} 
k+=1 ; 
} 
printf("最后正面向上的纸牌编号为:\n"); 
for(i=1;i<=52;i++) 
{ 
if(arr[i]==0)continue ; 
printf("%4d",arr[i]); 
} 
getch(); 

}