📄 loginhandler.java
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/*
* Generated by MyEclipse Struts
* Template path: templates/java/JavaClass.vtl
*/
package com.action;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.struts.action.Action;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.ActionMapping;
import com.dao.UserDao;
import com.form.LoginForm;
import com.po.User;
/**
* MyEclipse Struts
* Creation date: 05-16-2007
*
* XDoclet definition:
* @struts.action path="/login" name="loginForm" scope="request" validate="true"
* @struts.action-forward name="success" path="/success.jsp"
* @struts.action-forward name="failure" path="/login.jsp"
*/
public class LoginHandler extends Action {
private UserDao myUserDao;
/*
* Generated Methods
*/
public UserDao getMyUserDao() {
return myUserDao;
}
public void setMyUserDao(UserDao myUserDao) {
this.myUserDao = myUserDao;
}
/**
* Method execute
* @param mapping
* @param form
* @param request
* @param response
* @return ActionForward
*/
public ActionForward execute(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response) {
LoginForm loginForm = (LoginForm) form;// TODO Auto-generated method stub
//TODO
//构建User数据对象
User user = new User();
user.setUserName(loginForm.getUsername());
user.setPassword(loginForm.getPass());
//那么Struts的action如何获取Spring容器中的UserDao对象呢,只有一条路可走了,就是让
//Spring注入给你,如何注入呢?
//这就是Spring中用的最多的属性注入方式
//别急,继续配置Spring...
//从Spring容器中获取UserDao托管对象
boolean result = this.myUserDao.loginCheck(user);
//调用UserDao中得方法进行数据校验
if(result){
return mapping.findForward("success");
}else{
//根据返回值决定页面转向,true-跳转到成功页面;false-跳转到登陆页面进行重新登陆
return mapping.findForward("failure");
}
//至此,所有程序的开发已经结束,想想看,还有什么东西要做,哦,对了,数据库还没有,表还没有,跟别提表数据了
//还愣什么,快建啊
//ok,我已经搞定了,最后就是项目部署运行、调试了哈!
//初战告捷,接下来还有更加深入的学习内容,敬请期待...
}
}
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