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📄 example2_out.html.svn-base

📁 OPT++
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/** \page example2_out<pre>**********************************************************OPT++ version 2Job run at Thu Feb 14 17:30:20 2002Copyright (c) 2001, Sandia Corporation.  Under the terms of ContractDE-AC04-94AL85000, there is a non-exclusive license for use of thiswork by or on behalf of the U.S. Government.  Export of this program may require a license from the United States Government. This software is distributed under the GNU General Public License. For more information, see the COPYRIGHT and README files in the top OPT++ directory.**********************************************************		 NIPS Iteration Summary		Nonlinear Interior-Point Method Method with Trust Regions		 Initial Trust Region =   1.1384e-01    1   1.0743e+00   9.3086e-01  9.6100e-01   1.4982e+03    2   0   1.00e+02    2   1.8765e+00   9.3086e-01  1.3381e-01   7.2604e+02    4   1   1.00e+02    3   2.4281e+00   9.3086e-01  1.0000e+00   6.9547e+02    5   1   1.00e+02    4   1.2104e+00   9.3086e-03  9.3807e-01   1.4955e+02    6   1   1.00e+02    5   9.3918e-01   9.3086e-03  7.9395e-01   6.1965e+01    7   1   1.00e+02    6   9.6511e-01   9.3086e-03  1.0000e+00   3.8113e+01    8   1   1.00e+02    7   9.6301e-01   9.3086e-03  1.0000e+00   3.7888e+01    9   1   1.00e+02    8   9.5352e-01   9.3086e-05  9.9773e-01   1.6731e+00   10   1   1.00e+02    9   9.5362e-01   9.3086e-05  1.0000e+00   1.6229e+00   11   1   1.00e+02   10   9.5353e-01   9.3086e-07  1.0000e+00   9.6322e-01   12   1   1.00e+02L2 norm =   1.7443e-06  ftol =   1.0000e-06=========  Solution from nips  ===========Optimization method       = Nonlinear Interior-Point MethodDimension of the problem  = 3No. equalities            = 0No. inequalities          = 7Merit Function (0= NormFmu, 1 = Argaez, 2 = Vanderbei) = 1Return code               = 2 (OptNIPSLike: Algorithm converged)No. iterations taken      = 10No. function evaluations  = 12No. gradient evaluations  = 11=========  Solution from nips  ===========    i	    xc 		 grad 		 fcn_accrcy      1  3.6505e+00	 -5.9979e-01	  2.2204e-16     2  3.6505e+00	 -5.9979e-01	  2.2204e-16     3  4.6204e+00	 -7.5917e-01	  2.2204e-16Function Value     =   9.5353e-01Norm of gradient   =   1.1384e+00=======================================================  Solution from nips  ===========    i	   y    =====================================    i	    z 	      s    1  8.2153e-02  1.1190e-05    2  1.1416e-07  8.1505e+00    3  1.1416e-07  8.1505e+00    4  9.6695e-08  9.6204e+00    5  1.1004e-06  8.4954e-01    6  1.1004e-06  8.4954e-01    7  2.4932e-06  3.7958e-01==========  Tolerances  ===========Machine Epsilon      = 2.22045e-16Maximum Step         = 1000Minimum Step         = 1.49012e-08Maximum Iter         = 150Maximum Backtracks   = 5Maximum Fcn Eval     = 1000Step Tolerance       = 1.49012e-08Function Tolerance   = 1e-06Constraint Tolerance = 1.49012e-08Gradient Tolerance   = 6.05545e-06LineSearch Tolerance = 0.0001</pre>*/

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