an ldmicro tutorial.mht

用PIC單片機與AVR單片機製作PLC控制的階梯圖程序。

microcontrollers, but=20
            that you have never used LDmicro. If you don't know very =
much about=20
            ladder logic or PLCs, then <A=20
            href=3D"http://www.plcs.net/contents.shtml">the plcs.net =
tutorial</A>=20
            might be helpful to you.</P>
            <P>Our device will have one pushbutton, and one LED. At =
startup, the=20
            LED will be off. When you press the pushbutton once, the LED =
will=20
            turn steady on. The second time you press the pushbutton, =
the LED=20
            will start blinking. The third time that you press the =
button, the=20
            LED will turn off again. On subsequent presses, the cycle =
will=20
            repeat.</P>
            <H3>Microcontroller Selection and Schematic</H3>
            <P>We will be using a PIC16F876, which is easily available =
from=20
            Digikey or other online distributors. It comes in a number =
of=20
            different packages; I chose a DIP.</P>
            <P>This is our schematic:</P>
            <P><IMG style=3D"PADDING-LEFT: 10px"=20
            src=3D"http://cq.cx/pics/ldtut-schematic.png"></P>
            <P>The microcontroller (IC1) is part number =
PIC16F876-20I/SP-ND at=20
            <A href=3D"http://www.digikey.com/">Digikey.</A> Almost any=20
            three-terminal resonator (U1) will do; you might try a =
535-9356-ND=20
            or an X909-ND.</P>
            <P>The only thing that might confuse you is that the =
pushbutton goes=20
            to Vdd, and there is a pull-down. You might be more used to =
seeing a=20
            pushbutton to ground with a pull-up. For TTL, this mattered. =
For=20
            modern CMOS it does not, and I find this =91active HIGH=92 =
arrangement=20
            less confusing than the traditional =91active LOW=92 =
circuit.</P>
            <P>Also, I chose to use a ceramic resonator with internal=20
            capacitors, U1, instead of a crystal and two ~20&nbsp;pF =
caps. A=20
            crystal would work just as well and it would be more =
accurate, but=20
            it would be a little bit more expensive, and you would need =
more=20
            parts.</P>
            <P>You could build this circuit in many different ways. I =
built it=20
            on a solderless breadboard, and it ended up looking like =
this:</P>
            <P><IMG=20
            style=3D"BORDER-RIGHT: black 1px solid; BORDER-TOP: black =
1px solid; BORDER-LEFT: black 1px solid; BORDER-BOTTOM: black 1px solid" =

            src=3D"http://cq.cx/pics/ldtut-breadboard.jpg"></P>
            <P>(The resistor values pictured are not quite the same as =
the=20
            schematic; none of them are critical.)</P>
            <H3>Ladder Diagram for the Program</H3>
            <P>First, we are going to need an oscillator to generate the =

            =91blinking=92 signal for the LED. There is a standard way =
to do this in=20
            ladder logic:</P><PRE style=3D"FONT-SIZE: 13px; =
PADDING-BOTTOM: 10px; PADDING-TOP: 10px; font-face: Lucida Console">     =
    ||      Rosc            Tosc_on         Tosc_off           Rosc      =
 ||
       1 ||-------] [--------[TON 250.0 ms]---[TOF 250.0 =
ms]---------(/)-------||
</PRE>
            <P>This will flash at 1/((250+250)&nbsp;ms), or 2&nbsp;Hz, =
or twice=20
            per second. The duty cycle will be&nbsp;50%=97250&nbsp;ms =
on, then=20
            250&nbsp;ms off. This circuit can make any kind of =
oscillator, with=20
            whatever period or duty cycle you require, so it is a good =
one to=20
            remember.</P>
            <P>Also notice that we have chosen to use an internal relay =
(=91Rfoo=92)=20
            instead of one attached to an I/O pin (=91Yfoo=92 or =
=91Xfoo=92). This makes=20
            sense, because there is no particular reason to bring that =
signal=20
            out to a pin. LDmicro will automatically assign memory for =
the=20
            internal relay.</P>
            <P>Our program will have three states: off, steady on, and =
blinking.=20
            The program should change its state on each rising edge of =
the=20
            signal from the pushbutton. This is a good application for a =

            circular counter. We will say that =91state 0=92 is =
=91off,=92 =91state 1=92 is=20
            =91steady on,=92 and =91state 2=92 is =91blinking.=92 The =
counter counts 0, 1,=20
            2, 0, 1, 2, ..., so if we just let the rung-in condition of =
the=20
            counter be the pushbutton input, then everything will work =
like we=20
            want:</P><PRE style=3D"FONT-SIZE: 13px; PADDING-BOTTOM: =
10px; PADDING-TOP: 10px; font-face: Lucida Console">         ||     =
Xbutton                                            Cstate      ||
       2 ||-------] [---------------------------------------------{CTC =
0:2}----||
</PRE>
            <P>Now the only thing left is to use the program state to =
set the=20
            state of the LED. We can do it like this:</P><PRE =
style=3D"FONT-SIZE: 13px; PADDING-BOTTOM: 10px; PADDING-TOP: 10px; =
font-face: Lucida Console">         ||   [Cstate =3D=3D]                 =
                          Yled       ||
       3 ||---[ 1       ]-------------------+------------------------( =
)-------||
         ||                                 |                            =
      ||
         ||   [Cstate =3D=3D]         Rosc      |                        =
          ||
         ||---[ 2       ]----------] [------+                            =
      ||
</PRE>
            <P>It should be easy to convince yourself that this does =
what we=20
            want. If the program is in state 1, then the =91Cstate =
=3D=3D 1=92=20
            instruction energizes =91Yled=92, as desired. In state 2, =
the =91Cstate =3D=3D=20
            2=92 instruction energizes =91Yled=92, but only when =
=91Rosc=92 is also true.=20
            Since =91Rosc=92 is oscillating, that means that the LED =
will blink, as=20
            desired. Finally, in state 0, neither of the equals =
instructions=20
            will be true, so there is no way that =91Yled=92 could ever =
turn on.</P>
            <H3>Entering the Ladder Diagram</H3>
            <P>Now that we have our circuit, we can draw it in LDmicro. =
When you=20
            start LDmicro, you will see a single empty rung:</P>
            <P><IMG src=3D"http://cq.cx/pics/ldtut-empty-rung.png"></P>
            <P>We want to enter the first rung from the listing above. =
We will=20
            start with the coil, so choose Instruction -&gt; Insert =
Coil. This=20
            will create a coil named =91Ynew.=92 This is what we want, =
except that=20
            the name is wrong, and it should be negated. Double-click =
the coil;=20
            this will bring up a dialog where we can fill that in:</P>
            <P><IMG src=3D"http://cq.cx/pics/ldtut-osc-coil.png"></P>
            <P>Now we can insert the rest of that rung in the same way. =
Click on=20
            the left edge of the coil, so that the cursor is vertical, =
and to=20
            the left of the coil. Now choose Instruction -&gt; Insert =
TON=20
            (Delayed Turn On). Once again double-click the timer to =
rename it=20
            and set the period. Add the TOF timer and the contacts in =
the same=20
            way.</P>
            <P>Now we want to enter the second rung, so choose Edit =
-&gt; Insert=20
            Rung After. Then click on the second rung to move the cursor =

            there:</P>
            <P><IMG =
src=3D"http://cq.cx/pics/ldtut-second-rung-empty.png"></P>
            <P>The second rung is easy: just fill in the two =
instructions in the=20
            right order, by placing the cursor where you want to insert =
and then=20
            choosing Instruction -&gt; Insert .... Remember to assign a =
name=20
            (=91Xbutton=92) to the contacts, and to set the name and =
upper limit of=20
            the counter. Then choose Edit -&gt; Insert Rung After again. =
Your=20
            program should look like this:</P>
            <P><IMG =
src=3D"http://cq.cx/pics/ldtut-third-rung-empty.png"></P>
            <P>The third rung will be a bit trickier, because it has =
parallel=20
            branches. That means that you have to think about the order =
in which=20
            you insert the instructions. First, insert the coil, and =
rename=20
            it:</P>
            <P><IMG =
src=3D"http://cq.cx/pics/ldtut-third-rung-coil.png"></P>
            <P>Now insert the first equals instruction to the left of =
the coil,=20
            as usual, and fill in the correct variable name and value. =
After you=20
            do that, add the parallel branch. You can do this by =
clicking on the=20
            bottom edge of the equals instruction; the cursor will be =
horizontal=20
            and below that equals instruction:</P>
            <P><IMG =
src=3D"http://cq.cx/pics/ldtut-third-rung-one-cond.png"></P>
            <P>Now choose Instruction -&gt; Insert EQU (Compare for =
Equals).=20
            Since your cursor is below the first equals instruction, the =
new=20
            equals instruction will be inserted below that instruction, =
in=20
            parallel with it. Rename it as usual. To finish the rung, =
you must=20
            insert the =91Rosc=92 contacts to the right of the second =
equals=20
            instruction. To do this, click on the right edge of the =
second=20
            equals instruction:</P>
            <P><IMG =
src=3D"http://cq.cx/pics/ldtut-third-rung-both-cond.png"></P>
            <P>At this point you can choose Instruction -&gt; Insert =
Coil; the=20
            coil will be inserted in series with the second equals =
instruction,=20
            as you require. Rename it and you are done:</P>
            <P><IMG =
src=3D"http://cq.cx/pics/ldtut-third-rung-complete.png"></P>