📄 clrk4.m
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function [T,Y]=clrk4(f,a,b,m,y0)% CALL: [T,Y]=clrk4(f,a,b,m,y0) solves Ydot=f(T,Y) on t=[a,b].% INPUTS: f M-file defining input function; interval a,b; % m points in interval; y0 initial value% OUTPUTS: T abscissa, Y solution by 4th order Runge-Kutta methodh=(b-a)/(m-1); % Step sizeT=zeros(m,1); % Column vector of time pointsY=zeros(m,1); % Column vector of solution pointsT(1)=a;Y(1)=y0;for I=1:m-1; % There are m-1 steps and m points tI=T(I); % - step through m-1 intervals yI=Y(I); k1=h*feval(f,tI,yI); % Runge-Kutta coefficients k2=h*feval(f,tI+h/2,yI+k1/2); k3=h*feval(f,tI+h/2,yI+k2/2); k4=h*feval(f,tI+h,yI+k3); Y(I+1)=yI+(k1+2*k2+2*k3+k4)/6; T(I+1)=a + h*I; % Next time stepend%% Version 5 Changed T,Y to column vectors%
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