📄 ex4_5.m
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% EX4_5.M Verify Example 4.5 and demonstrate Equation4.20% INPUT: Battery Voltage values [V1 V2]% OUTPUT: Current in the loops V=input('Battery voltage in loop 1 and 2 [V1 V2]= ')va=[1 1]'; % Eigenvectorsvb=[1 -1]';c1=(V(1)+V(2))/2; % Compute coefficientsc2=(V(1)-V(2))/2;fprintf(' The currents are as follows')i=(1/3)*c1*va + c2*vb
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