ac1264.pas
来自「这是在网络上搜集到的在东京大学的ACM上面解决的一些题目的源码」· PAS 代码 · 共 24 行
PAS
24 行
{$Q-,R-}
program tju1264;
const
maxn=1000000;
var
d:array[1..maxn]of word;
bq,sq:array[1..maxn]of longint;
n,k,i,bf,br,sf,sr,head,ans,m:longint;
begin
repeat
read(n,k);
bf:=1;br:=0;sf:=1;sr:=0;head:=0;ans:=0;
for i:=1 to n do begin
read(d[i]);
while (br>=bf) and (d[i]>=d[bq[br]]) do dec(br);inc(br);bq[br]:=i;
while (sr>=sf) and (d[i]<=d[sq[sr]]) do dec(sr);inc(sr);sq[sr]:=i;
if d[bq[bf]]-d[i]>k then begin repeat inc(bf);until d[bq[bf]]-d[i]<=k;head:=bq[bf-1];end;
if d[i]-d[sq[sf]]>k then begin repeat inc(sf);until d[i]-d[sq[sf]]<=k;head:=sq[sf-1];end;
if i-head>ans then ans:=i-head;
end;
writeln(ans);
until seekeof;
end.
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