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📄 exs5.m

📁 用于在matlab平台上进行有限元分析
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% example exs5%----------------------------------------------------------------% PURPOSE %    Analysis of a simply supported beam.%----------------------------------------------------------------% REFERENCES%     G"oran Sandberg 94-03-08 %     Karl-Gunnar Olsson 95-09-28%     Ola Dahlblom 2004-09-21%---------------------------------------------------------------- echo on%----- Topology ------------------------------------------------- Edof=[1  1  2  3  4  5  6;       2  4  5  6  7  8  9;         3  7  8  9 10 11 12];%----- Stiffness matrix K and load vector f --------------------- K=zeros(12);   f=zeros(12,1); f(5)=-10000;%----- Element stiffness matrices  ------------------------------ E=2.1e11;     A=45.3e-4;     I=2510e-8;      ep=[E A I]; ex=[0 3];     ey=[0 0]; Ke=beam2e(ex,ey,ep)%----- Assemble Ke into K --------------------------------------- K=assem(Edof,K,Ke);%----- Solve the system of equations and compute support forces - bc=[1 0; 2 0; 11 0]; [a,r]=solveq(K,f,bc);%----- Section forces ------------------------------------------- Ed=extract(Edof,a); es1=beam2s(ex,ey,ep,Ed(1,:)); es2=beam2s(ex,ey,ep,Ed(2,:)); es3=beam2s(ex,ey,ep,Ed(3,:));%----- Results -------------------------------------------------- a r es1 es2 es3%------------------------ end ----------------------------------- echo off

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