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Subject: Circuit explanation of +30V power supply
Date: Fri Oct 05 2007 19:00:18 GMT+0800
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tion of +30V power supply</title>
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[<a href=3D"http://www.interq.or.jp/japan/se-inoue/e_menu.htm">Menu</a>]>=
[<a href=3D"http://www.interq.or.jp/japan/se-inoue/e_ckt.htm">Electronic cir=
cuit beans collection</a>]>[<a href=3D"http://www.interq.or.jp/japan/se-i=
noue/e_ckt27.htm">+30V Power</a>]<br>
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<font color=3D"#800000" size=3D"6">Circuit explanation for +30V power supply=
</font><br>
<img src=3D"index_files/line_001.gif" alt=3D"" align=3D"bottom" height=3D"13=
" width=3D"454"><br>
<br>
<table cellpadding=3D"10" width=3D"95%">
<tbody><tr>
<td bgcolor=3D"#ffffff">
<a name=3D"1"></a><img src=3D"index_files/blank_1.gif" alt=3D"" align=3D"bot=
tom" height=3D"11" width=3D"11"><br>
<img src=3D"index_files/bol_org.gif" alt=3D"" align=3D"bottom" height=3D"16"=
width=3D"16"><font size=3D"4"><b> </b>The oscillation circuit</font><br>
<br>
<img src=3D"index_files/ckt27_31.gif" alt=3D"" align=3D"left" height=3D"131"=
hspace=3D"10" width=3D"196"><br>
<font size=3D"2">The inverter which has the hysteresis characteristic is
used as the oscillation circuit. The output wave form of the oscillator
is the square wave. The oscillation frequency can be changed by VR1.
The control of the oscillation frequency is used for the adjustment of
the output voltage. The circuit which was made this time could be
changed from 334KHz to 12,650KHz. The frequency with the upper limit
depends on the high frequency characteristic of the IC.</font><br>
<br clear=3D"left">
<font size=3D"2">As for the operation of the oscillator which used the inver=
ter, refer to "</font><a href=3D"http://www.interq.or.jp/japan/se-inoue/e_ck=
t13.htm"><font size=3D"2">Square wave oscillator</font></a><font size=3D"2">=
".</font><br>
<br>
<hr><br>
<a name=3D"2"></a><img src=3D"index_files/blank_1.gif" alt=3D"" align=3D"bot=
tom" height=3D"11" width=3D"11"><br>
<img src=3D"index_files/bol_org.gif" alt=3D"" align=3D"bottom" height=3D"16"=
width=3D"16"><font size=3D"4"><b> </b>The current amplification circuit</fo=
nt><br>
<br>
<img src=3D"index_files/ckt27_32.gif" alt=3D"" align=3D"left" height=3D"120"=
hspace=3D"10" width=3D"196"><br>
<font size=3D"2">It depends on the kind of the IC but the many electric curr=
ents which are gotten from the one inverter don't occur.</font><br>
<font size=3D"2">In case of 74HC14, the maximum electric current which
can be passed with the inverter of the 1 circuit is 4 mA. Because it
is, the one inverter is OK but connects the inverter in parallel for
the safety. In case of 74HC14, the six inverters are housed in the one
package. At the circuit this time, the four inverters are connected in
parallel. The inverter immediately behind the inverter for the
oscillation is for the buffer. It is the one to make that the change of
the load current influences the oscillation little. I think that it is
permitted to do the five inverters in the multiple connection without
using the buffer.</font><br>
<font size=3D"2">Generally, among the output of the logic circuit aren't
connected. It is because the output competes when the different signal
is inputted and the IC has broken.</font><br>
<font size=3D"2">In case of the circuit this time, because all input
signals are the same, they can connect the output in parallel. However,
strictly, it is not the good way.</font><br>
<br clear=3D"left">
<hr><br>
<a name=3D"3"></a><img src=3D"index_files/blank_1.gif" alt=3D"" align=3D"bot=
tom" height=3D"11" width=3D"11"><br>
<img src=3D"index_files/bol_org.gif" alt=3D"" align=3D"bottom" height=3D"16"=
width=3D"16"><font size=3D"4"><b> </b>The resonance circuit</font><br>
<br>
<img src=3D"index_files/ckt27_331.gif" alt=3D"" align=3D"left" height=3D"130=
" width=3D"253"><br>
<font size=3D"2">As for the square wave signal which was made with the
oscillator, the maximum voltage is 5Vp-p(Low:0V, High:+5V). current
signal by the resonance circuit which used the coil and the capacitor.</font=
><br>
<font size=3D"2">The positive and the negatively changing alternating
current signal are composed of the resonance circuit. The resonant
frequency becomes the frequency to take out.</font><br>
<font size=3D"2">The resonant frequency is calculated in </font><img src=3D"=
index_files/2pai_lc.gif" alt=3D"" align=3D"bottom" height=3D"13" width=3D"93=
"><font size=3D"2">. When calculating as L =3D 18 =B5H, C =3D 330 pF, the re=
sonant frequency becomes about 2 MHz.</font><br>
<br clear=3D"left">
<br>
<div align=3D"center"><img src=3D"index_files/ckt27_332.gif" alt=3D"" align=
=3D"bottom" height=3D"218" width=3D"385"><br></div>
<br>
<font size=3D"2">At the circuit which I made, the resonant frequency was 2,1=
40 KHz.</font><br>
<br>
<hr><br>
<a name=3D"4"></a><img src=3D"index_files/blank_1.gif" alt=3D"" align=3D"bot=
tom" height=3D"11" width=3D"11"><br>
<img src=3D"index_files/bol_org.gif" alt=3D"" align=3D"bottom" height=3D"16"=
width=3D"16"><font size=3D"4"><b> </b>The voltage amplification rectificati=
on circuit</font><br>
<br>
<font size=3D"2">This is the circuit which gets about twice of DC voltages f=
rom the inputted alternating voltage.</font><br>
<br>
<img src=3D"index_files/ckt27_341.gif" alt=3D"" align=3D"left" height=3D"111=
" width=3D"224"><br>
<font size=3D"2">In the period with the negative voltage of the input
alternating current signal, the electric charge is stored up to the
capacitor (C) through D1. With this, the voltage of the both edges of
the capacitor becomes Vc.</font><br>
<br clear=3D"left">
<img src=3D"index_files/ckt27_342.gif" alt=3D"" align=3D"left" height=3D"120=
" width=3D"224"><br>
<font size=3D"2">Next, in the period with the positive voltage with the
input alternating voltage, the input voltage (Vi) and the voltage (Vc)
of the capacitor are gained and the voltage of Vi+Vc is output.</font><br>
<font size=3D"2">The value of Vi and Vc are changed by the frequency of
the input alternating current or the electric current which flows
through the load.</font><br>
<br clear=3D"left">
<br>
<font size=3D"2">The circuit this time works in the high frequency switching=
. Because it is, as the diode, </font><a href=3D"http://www.interq.or.jp/jap=
an/se-inoue/e_diode.htm#diode4"><font size=3D"2">the shottky barrier diode</=
font></a><font size=3D"2"> with the short recovery time must be used.</font>=
<br>
<br>
<hr><br>
<a name=3D"5"></a><img src=3D"index_files/blank_1.gif" alt=3D"" align=3D"bot=
tom" height=3D"11" width=3D"11"><br>
<img src=3D"index_files/bol_org.gif" alt=3D"" align=3D"bottom" height=3D"16"=
width=3D"16"><font size=3D"4"><b> </b>The ripple filter circuit</font><br>
<br>
<img src=3D"index_files/ckt27_35.gif" alt=3D"" align=3D"left" height=3D"206"=
hspace=3D"10" vspace=3D"10" width=3D"273"><br>
<font size=3D"2">As for the DC voltage which is output from the voltage
amplification rectification circuit, the half wave was rectified. So,
the ripple is contained in the output. The ripple filter circuit is
used to make this ripple little. The circuit this time is using the
resistor instead of the coil. Therefore, the output voltage falls at
more when the output current increases.</font><br>
<br clear=3D"left">
<br>
<img src=3D"index_files/blank_1.gif" alt=3D"" align=3D"bottom" height=3D"11"=
width=3D"11"></td>
</tr>
</tbody></table><br>
<br>
<img src=3D"index_files/blank_1.gif" alt=3D"" align=3D"bottom" height=3D"11"=
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