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📄 cpu.m

📁 8个进程的改进版CPU schedule 算法-FCFS
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%--------------------------------------------------------------------------
clc;
clear;
%--------------------------------------------------------------------------
GlobalCycle=0;
EndTime=2000;
DiskTime=5;
Ts=1;

NProcess=3;
Qlen=NProcess;
TB=[200;10;10];

QReady=[1 0;
        2 0;
        3 0]; %  1 col is the process name;2 col is the remaining bust time
QReady(:,2)=TB

QReady_WaitTime=zeros(NProcess,1);
QReady_History=zeros(2*NProcess+3,EndTime);
 
QDisk=zeros(NProcess,2);  %  1 col is the process name;2 col is the endtime
QDisk(:,2)=EndTime;       %  initial the endtime to the EndTime

%--------------------------------------------------------------------------
while GlobalCycle<EndTime
  curP=0;  %make sure not store the old state, 0 mean the cpu is idle  
  [QDisk,QReady]=CheckDiskQueue_FCFSorSJF(QDisk,QReady,Qlen,GlobalCycle,TB,EndTime); %......
  
  
  if sum(QReady(:,1))==0
      QReady_History(:,GlobalCycle)=0;
      fprintf('CPU idle at T=%d....\n',GlobalCycle);
      
      QReady_History(:,GlobalCycle+1)=-1;% Idle state
      GlobalCycle=GlobalCycle+1;
      continue;
  end
  %--------------------we know there are processes in the ReadQueue------------------
  
  [curP,QReady]=FCFS(QReady,Qlen); %pick up a process
  
  QReady_History(:,GlobalCycle+1)=[QReady(:,1);0;QDisk(:,1);0;curP];% the current state
  
%    for i=GlobalCycle:GlobalCycle+Ts
%        QReady_History(:,i+1)=QReady(:,1);% the current state
%    end
       
   GlobalCycle=GlobalCycle+TB(curP);
   GlobalCycle=GlobalCycle+Ts;
   
   value=GlobalCycle+DiskTime;
   [QDisk,pos]=InQueue2(curP,value,QDisk,Qlen); %put into the DiskQueue
   
end

OutputResult(QReady_History,EndTime,NProcess);
Analysis(QReady_History,TB,1);

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