checkmonotonicallyincreasingnumbers.java
来自「JGRoups源码」· Java 代码 · 共 73 行
JAVA
73 行
package org.jgroups.tests;import java.io.*;/** * Checks whether numbers in a stream are monotonically increasing, e.g. * <pre> * 1 * 2 * 3 * 4 * </pre> * @author Bela Ban * @version $Id: CheckMonotonicallyIncreasingNumbers.java,v 1.2 2006/01/16 13:01:26 belaban Exp $ */public class CheckMonotonicallyIncreasingNumbers { static int check(InputStream in) throws IOException { Reader r = new BufferedReader(new InputStreamReader(in)); StreamTokenizer st = new StreamTokenizer(r); int i, cnt=0, num=0, tmp, incorrect=0; boolean first_read=false; while(true) { i=st.nextToken(); if(i == StreamTokenizer.TT_EOF) break; tmp=(int)st.nval; if(!first_read) { first_read=true; } else { if(tmp != num +1) { System.err.println("Number read: " + tmp + ", previous number: " + num + " (lineno: " + st.lineno() + ")"); incorrect++; } } num=tmp; cnt++; if(cnt > 0 && cnt % 1000 == 0) System.out.println("read " + cnt + " numbers"); } return incorrect; } public static void main(String[] args) throws IOException { String file=null; for(int i=0; i < args.length; i++) { if(args[i].equals("-file")) { file=args[++i]; continue; } help(); return; } FileInputStream fis=new FileInputStream(file); int incorrect=CheckMonotonicallyIncreasingNumbers.check(fis); if(incorrect == 0) { System.out.println("OK, all numbers are monotonically increasing"); } else { System.err.println("Failure: there are " + incorrect + " incorrect numbers"); } fis.close(); } private static void help() { System.out.println("CheckMonotonicallyIncreasingNumbers [-help] [-file <filename>]"); }}
⌨️ 快捷键说明
复制代码Ctrl + C
搜索代码Ctrl + F
全屏模式F11
增大字号Ctrl + =
减小字号Ctrl + -
显示快捷键?