phrasepositions.java

来自「lucene2.2.0版本」· Java 代码 · 共 82 行

JAVA
82
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package org.apache.lucene.search;/** * Licensed to the Apache Software Foundation (ASF) under one or more * contributor license agreements.  See the NOTICE file distributed with * this work for additional information regarding copyright ownership. * The ASF licenses this file to You under the Apache License, Version 2.0 * (the "License"); you may not use this file except in compliance with * the License.  You may obtain a copy of the License at * *     http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. */import java.io.IOException;import org.apache.lucene.index.*;/** * Position of a term in a document that takes into account the term offset within the phrase.  */final class PhrasePositions {  int doc;					  // current doc  int position;					  // position in doc  int count;					  // remaining pos in this doc  int offset;					  // position in phrase  TermPositions tp;				  // stream of positions  PhrasePositions next;				  // used to make lists  boolean repeats;       // there's other pp for same term (e.g. query="1st word 2nd word"~1)   PhrasePositions(TermPositions t, int o) {    tp = t;    offset = o;  }  final boolean next() throws IOException {	  // increments to next doc    if (!tp.next()) {      tp.close();				  // close stream      doc = Integer.MAX_VALUE;			  // sentinel value      return false;    }    doc = tp.doc();    position = 0;    return true;  }  final boolean skipTo(int target) throws IOException {    if (!tp.skipTo(target)) {      tp.close();				  // close stream      doc = Integer.MAX_VALUE;			  // sentinel value      return false;    }    doc = tp.doc();    position = 0;    return true;  }  final void firstPosition() throws IOException {    count = tp.freq();				  // read first pos    nextPosition();  }  /**   * Go to next location of this term current document, and set    * <code>position</code> as <code>location - offset</code>, so that a    * matching exact phrase is easily identified when all PhrasePositions    * have exactly the same <code>position</code>.   */  final boolean nextPosition() throws IOException {    if (count-- > 0) {				  // read subsequent pos's      position = tp.nextPosition() - offset;      return true;    } else      return false;  }}

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