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📄 filesystemresourceloader.java

📁 Spring API核心源代码 Spring API核心源代码 Spring API核心源代码
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/*
 * Copyright 2002-2007 the original author or authors.
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *      http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

package org.springframework.core.io;

/**
 * {@link ResourceLoader} implementation that resolves plain paths as
 * file system resources rather than as class path resources
 * (the latter is {@link DefaultResourceLoader}'s default strategy).
 *
 * <p><b>NOTE:</b> Plain paths will always be interpreted as relative
 * to the current VM working directory, even if they start with a slash.
 * (This is consistent with the semantics in a Servlet container.)
 * <b>Use an explicit "file:" prefix to enforce an absolute file path.</b>
 *
 * <p>{@link org.springframework.context.support.FileSystemXmlApplicationContext}
 * is a full-fledged ApplicationContext implementation that provides
 * the same resource path resolution strategy.
 *
 * @author Juergen Hoeller
 * @since 1.1.3
 * @see DefaultResourceLoader
 * @see org.springframework.context.support.FileSystemXmlApplicationContext
 */
public class FileSystemResourceLoader extends DefaultResourceLoader {

	/**
	 * Resolve resource paths as file system paths.
	 * <p>Note: Even if a given path starts with a slash, it will get
	 * interpreted as relative to the current VM working directory.
	 * @param path path to the resource
	 * @return Resource handle
	 * @see FileSystemResource
	 * @see org.springframework.web.context.support.ServletContextResourceLoader#getResourceByPath
	 */
	protected Resource getResourceByPath(String path) {
		if (path != null && path.startsWith("/")) {
			path = path.substring(1);
		}
		return new FileSystemResource(path);
	}

}

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