25点阵式led“0－9”数字显示技术.c

C51学习书

#include <reg51.h> 
//25．            点阵式LED"0－9"数字显示技术
unsigned char code tab[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f}; 
unsigned char code digittab[10][8]={	　 {0x00,0x00,0x3e,0x41,0x41,0x41,0x3e,0x00},	//0 
                                    {0x00,0x00,0x00,0x00,0x21,0x7f,0x01,0x00},	//1 
                                    {0x00,0x00,0x27,0x45,0x45,0x45,0x39,0x00},	//2 
                                    {0x00,0x00,0x22,0x49,0x49,0x49,0x36,0x00},	//3 
                                    {0x00,0x00,0x0c,0x14,0x24,0x7f,0x04,0x00},	//4 
                                    {0x00,0x00,0x72,0x51,0x51,0x51,0x4e,0x00},	//5 
                                    {0x00,0x00,0x3e,0x49,0x49,0x49,0x26,0x00},	//6 
                                    {0x00,0x00,0x40,0x40,0x40,0x4f,0x70,0x00},	//7 
                                    {0x00,0x00,0x36,0x49,0x49,0x49,0x36,0x00},	//8 
                                    {0x00,0x00,0x32,0x49,0x49,0x49,0x3e,0x00}	//9 
                                    }; 
  
unsigned int timecount; 
unsigned char cnta; 
unsigned char cntb; 
  
void main(void) 
{ 
  TMOD=0x01; 
  TH0=(65536-3000)/256; 
  TL0=(65536-3000)%256; 
  TR0=1; 
  ET0=1; 
  EA=1; 
  while(1) 
    {; 
    } 
} 
  
void t0(void) interrupt 1 using 0 
{ 
  TH0=(65536-3000)/256; 
  TL0=(65536-3000)%256; 
  P3=tab[cnta]; 
  P1=digittab[cntb][cnta]; 
  cnta++; 
  if(cnta==8) 
    { 
      cnta=0; 
    } 
  timecount++; 
  if(timecount==333) 
    { 
      timecount=0; 
      cntb++; 
      if(cntb==10) 
        { 
          cntb=0; 
        } 
    } 
}