📄 飞机着陆控制.mht
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<p class=3DMsoNormal><span style=3D'font-family:SimSun;mso-ascii-font-=
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2320;高度</span></p>
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<p class=3DMsoNormal><span style=3D'font-family:SimSun;mso-ascii-font-=
family:
"Times New Roman";mso-hansi-font-family:"Times New Roman"'>下=
8477;速度</span></p>
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本框: 下降速度"
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<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'><span
style=3D'font-family:SimSun;mso-ascii-font-family:"Times New Roman";mso-han=
si-font-family:
"Times New Roman"'>图</span><span lang=3DEN-US>1 </span><span
style=3D'font-family:SimSun;mso-ascii-font-family:"Times New Roman";mso-han=
si-font-family:
"Times New Roman"'>着陆速度作为高=
度的函数的期望曲线</s=
pan></p>
<p class=3DMsoNormal style=3D'text-indent:26.25pt;mso-char-indent-count:2.5=
'><span
style=3D'font-family:SimSun;mso-ascii-font-family:"Times New Roman";mso-han=
si-font-family:
"Times New Roman"'>上述所需的模型=
的两个状态变量是离=
2320;高度</span><span
lang=3DEN-US>h</span><span style=3D'font-family:SimSun;mso-ascii-font-famil=
y:"Times New Roman";
mso-hansi-font-family:"Times New Roman"'>和飞机垂&#=
30452;速度的</span><span
lang=3DEN-US>v</span><span style=3D'font-family:SimSun;mso-ascii-font-famil=
y:"Times New Roman";
mso-hansi-font-family:"Times New Roman"'>(图</span><span
lang=3DEN-US>2</span><span style=3D'font-family:SimSun;mso-ascii-font-famil=
y:"Times New Roman";
mso-hansi-font-family:"Times New Roman"'>)。控制&#=
36755;出的是作用于飞机×=
16;时又能改变飞机高度=
</span><span
lang=3DEN-US>h</span><span style=3D'font-family:SimSun;mso-ascii-font-famil=
y:"Times New Roman";
mso-hansi-font-family:"Times New Roman"'>和速度</span><sp=
an
lang=3DEN-US>v</span><span style=3D'font-family:SimSun;mso-ascii-font-famil=
y:"Times New Roman";
mso-hansi-font-family:"Times New Roman"'>的作用力&#=
12290;下面给出了与此密Ñ=
99;相关的口感乃至微分=
方程式,见图</span><span
lang=3DEN-US>3</span><span style=3D'font-family:SimSun;mso-ascii-font-famil=
y:"Times New Roman";
mso-hansi-font-family:"Times New Roman"'>。以速度</=
span><span
lang=3DEN-US>v</span><span style=3D'font-family:SimSun;mso-ascii-font-famil=
y:"Times New Roman";
mso-hansi-font-family:"Times New Roman"'>运动的质&#=
37327;</span><span
lang=3DEN-US>m</span><span style=3D'font-family:SimSun;mso-ascii-font-famil=
y:"Times New Roman";
mso-hansi-font-family:"Times New Roman"'>具有动量</=
span><span
lang=3DEN-US>p=3D<span class=3DSpellE>mv</span></span><span style=3D'font-f=
amily:SimSun;
mso-ascii-font-family:"Times New Roman";mso-hansi-font-family:"Times New Ro=
man"'>。如果没有外部力ŵ=
27;的作用,该质量将以=
同样的速度</span><span
lang=3DEN-US>v</span><span style=3D'font-family:SimSun;mso-ascii-font-famil=
y:"Times New Roman";
mso-hansi-font-family:"Times New Roman"'>向同样的&#=
26041;向运动。如果在时ſ=
88;间隔△</span><span
lang=3DEN-US>t</span><span style=3D'font-family:SimSun;mso-ascii-font-famil=
y:"Times New Roman";
mso-hansi-font-family:"Times New Roman"'>内,<span class=3DGram=
E>有个力</span></span><span
lang=3DEN-US>f</span><span style=3D'font-family:SimSun;mso-ascii-font-famil=
y:"Times New Roman";
mso-hansi-font-family:"Times New Roman"'>作用,那&#=
20040;就会有速度△</span><span
lang=3DEN-US>v</span><span style=3D'font-family:SimSun;mso-ascii-font-famil=
y:"Times New Roman";
mso-hansi-font-family:"Times New Roman"'>=</span><span lang=3DEN-US>=
f</span><span
style=3D'font-family:SimSun;mso-ascii-font-family:"Times New Roman";mso-han=
si-font-family:
"Times New Roman"'>△</span><span lang=3DEN-US>t/m</span><span
style=3D'font-family:SimSun;mso-ascii-font-family:"Times New Roman";mso-han=
si-font-family:
"Times New Roman"'>存在。如果我们=
取△</span><span
lang=3DEN-US>t</span><span style=3D'font-family:SimSun;mso-ascii-font-famil=
y:"Times New Roman";
mso-hansi-font-family:"Times New Roman"'>=</span><span lang=3DEN-US>=
1.0s</span><span
style=3D'font-family:SimSun;mso-ascii-font-family:"Times New Roman";mso-han=
si-font-family:
"Times New Roman"'>和</span><span lang=3DEN-US>m</span><span
style=3D'font-family:SimSun;mso-ascii-font-family:"Times New Roman";mso-han=
si-font-family:
"Times New Roman"'>=</span><span lang=3DEN-US>1.0</span><span
style=3D'font-family:SimSun;mso-ascii-font-family:"Times New Roman";mso-han=
si-font-family:
"Times New Roman"'>(</span><span lang=3DEN-US>lb-<sub><!--[if gte vm=
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amily:
"Times New Roman";mso-hansi-font-family:"Times New Roman"'>英尺=
),则可得△</span><span
lang=3DEN-US>v</span><span style=3D'font-family:SimSun;mso-ascii-font-famil=
y:"Times New Roman";
mso-hansi-font-family:"Times New Roman"'>=</span><span lang=3DEN-US>=
f</span><span
style=3D'font-family:SimSun;mso-ascii-font-family:"Times New Roman";mso-han=
si-font-family:
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style=3D'font-family:SimSun;mso-ascii-font-family:"Times New Roman";mso-han=
si-font-family:
"Times New Roman"'>),或正比于作=
用力的速度变化量。</s=
pan></p>
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<p class=3DMsoNormal align=3Dcenter style=3D'text-align:center'><span
style=3D'font-family:SimSun;mso-ascii-font-family:"Times New Roman";mso-han=
si-font-family:
"Times New Roman"'>图</span><span lang=3DEN-US>2 </span><span
style=3D'font-family:SimSun;mso-ascii-font-family:"Times New Roman";mso-han=
si-font-family:
"Times New Roman"'>飞机着陆控制问=
题</span></p>
<p class=3DMsoNormal><span style=3D'font-family:SimSun;mso-ascii-font-famil=
y:"Times New Roman";
mso-hansi-font-family:"Times New Roman"'>其差分表&#=
31034;法为:</span></p>
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<p class=3DMsoNormal><span style=3D'font-family:SimSun;mso-ascii-font-famil=
y:"Times New Roman";
mso-hansi-font-family:"Times New Roman"'>这里</span><span
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amily:
"Times New Roman";mso-hansi-font-family:"Times New Roman"'>是新=
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</xml><![endif]--></span><span style=3D'font-family:SimSun;mso-ascii-font-f=
amily:
"Times New Roman";mso-hansi-font-family:"Times New Roman"'>是原=
速度。</span><span
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