step2.html

ajax快速入门,主要讲解原理与部门实现

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var xmlHttp=new ActiveXObject("Msxml2.XMLHTTP");
xmlHttp.open("GET", "http://www.blogjava.net/zbw25/Rss.aspx", true);
xmlHttp.onreadystatechange=function() {
    if (xmlHttp.readyState==4) {
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xmlHttp.send(null);
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<div id="content"></div>