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📄 wavelet.m

📁 小波变换所有常见例程
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  g0 = [0,a;0,sqrt(2)*a];  g1 = [b,c;sqrt(2)*b,sqrt(2)*c];  g2 = [-1,c;0,-sqrt(2)*c];  g3 = [b,a;-sqrt(2)*b,-sqrt(2)*a];  H = mpoly({[h0;g0],[h1;g1],[h2;g2],[h3;g3]},-2,'symbol',2,2);   H = H/2;  ht0 = [0,at;0,0];  ht1 = [bt,ct;0,0];  ht2 = [1,ct;0,dt];  ht3 = [bt,at;et,dt];  gt0 = [0,at;0,sqrt(2)*at];  gt1 = [bt,ct;sqrt(2)*bt,sqrt(2)*ct];  gt2 = [-1,ct;0,-sqrt(2)*ct];  gt3 = [bt,at;-sqrt(2)*bt,-sqrt(2)*at];  Ht = mpoly({[ht0;gt0],[ht1;gt1],[ht2;gt2],[ht3;gt3]},-2,'symbol',2,2);   Ht = Ht/2; case 'jrzb'%  Full form: 'jrzb', s, t, lambda, mu%  Jia-Riemenschneider-Zhou biorthogonal, |2 lambda + mu| < 2.%  scaling function only; wavelet functions / dual not known%  symmetric, m=2, r=2, l=3, support [0,2], p=1%%  R.-Q. Jia, S. D. Riemenschneider, and D.-X. Zhou, Vector%        Subdivision Schemes and Multiple Wavelets, Math. Comp. 67 (1998),%        pp. 1533 - 1563  s = varargin{1};  t = varargin{2};  lambda = varargin{3};  mu = varargin{4};  h0 = [1/4,s/4;t/2,lambda/2];  h1 = [1/2,0;0,mu/2];  h2 = [1/4,-s/4;-t/2,lambda/2];  H = mpoly({h0,h1,h2},0,'symbol',2,2);  otherwise  error('unknown type of wavelet');endif symbolic    returnendH = double(H);if (nargout >= 2)    Ht = double(Ht);end%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%                                                                       %%  End of main program                                                  %%  The rest are routines that calculate some special types of wavelets  % %  (Daubechies, Cohen)                                                  %%                                                                       %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%function S = daubechies(p,type)% DAUBECHIES --  produce symbol of Daubechies wavelet%%        H = daubechies(p,type)%% Calculates the coefficients for the Daubechies wavelet with p% vanishing moments, and returns them as a symbol. If type = 1 (or% omitted), this routine calculates the original Daubechies wavelets% as given in%  %        Ingrid Daubechies%        Orthonormal Bases of Compactly Supported Wavelets%        Comm. Pure Appl. Math. 41 (1988), p. 909 - 996%% Otherwise, it calculates the least asymmetric Daubechies% wavelets, as defined in section 2 of%%        Ingrid Daubechies%        Orthonormal Bases of Compactly Supported Wavelets II:%            Variations on a Theme%        Siam J. Math. Anal., vol. 24, no. 2, March 1993%        p. 499 - 519%        % For p <= 3, the two types are identical.      %% The algorithm is that given in chapter 6 of Daubechies' book "Ten% Lectures on Wavelets" (TLW).%  % In all cases, there are really two solutions, one of them being the% other one in reverse. I have not been able to find any standard% choice in the literature or in other people's programs. My choice% is to select the ordering so that the largest coefficient occurs in% the first half. The peak and center of mass of the scaling function% are therefore also to the left of center. If you are trying to% duplicate some results from the literature, make sure to check that% you are using the same wavelet. Likewise, someone else's% coefficients may have a minus sign attached to the high-pass% coefficients.%% For p = 1, 2, 3, the coefficients are returned in symbolic form.% For larger p, the coefficients are always numeric.if (round(p) ~= p | p < 1)    error('p must be an integer >=1');endif (nargin < 2)    type = 1;endif (p == 1)    S = mpoly({sym('[1/2;1/2]'),sym('[1/2;-1/2]')},0,'symbol',2,1);    return;endif (p == 2)    S = mpoly({sym('[1+sqrt(3);1-sqrt(3)]'),...	       sym('[3+sqrt(3);-3+sqrt(3)]'),...	       sym('[3-sqrt(3);3+sqrt(3)]'),...	       sym('[1-sqrt(3);-1-sqrt(3)]')},0,'symbol',2,1);    S = S/8;    returnendif (p == 3)    S = mpoly({sym('[1+sqrt(10)+sqrt(5+2*sqrt(10));1+sqrt(10)-sqrt(5+2*sqrt(10))]'),...	       sym('[5+sqrt(10)+3*sqrt(5+2*sqrt(10));-5-sqrt(10)+3*sqrt(5+2*sqrt(10))]'),...	       sym('[10-2*sqrt(10)+2*sqrt(5+2*sqrt(10));10-2*sqrt(10)-2*sqrt(5+2*sqrt(10))]'),...	       sym('[10-2*sqrt(10)-2*sqrt(5+2*sqrt(10));-10+2*sqrt(10)-2*sqrt(5+2*sqrt(10))]'),...	       sym('[5+sqrt(10)-3*sqrt(5+2*sqrt(10));5+sqrt(10)+3*sqrt(5+2*sqrt(10))]'),...	       sym('[1+sqrt(10)-sqrt(5+2*sqrt(10));-1-sqrt(10)-sqrt(5+2*sqrt(10))]')},...	       0,'symbol',2,1);    S = S/32;    returnend%  Compute polynomial P = P_p(y) (eq. 6.1.12 in TLW)k = 0:p-1;P = mpoly(reshape(binomial(p-1+k,k),1,1,p));%  Convert P_p(y), y = sin^2(w/2) to form Q(z), z = exp(iw)y = mpoly({-1/4,1/2,-1/4},-1);Q = P(y);%  Find the roots of Qr = roots(Q.coef(:));%  Now we need to select one root out of each real pair, or one pair%  out of each complex quadruple.%%  If type == 1, we choose the roots outside the unit disk.%  If type ~= 1, we have to generate all possible choices, and%  calculate the deviation from symmetry for each one.if (type == 1)    r = r(find(abs(r)>1));else    %  choose one root from each group (real pair or complex quadruple)    r = r(find(abs(r)>1 & imag(r) >= 0));    %  generate all possibilities for inverting any element of r except    %  the first    R = r;    l = length(r);    for k = 2:l	s = R;	s(k,:) = 1 ./ s(k,:);	R = [R s];    end    %  calculate max(abs(psi_tot)) for all of them, select the smallest    P = zeros(1,2^(l-1));    for k = 1:2^(l-1)	P(k) = psi_tot(R(:,k));    end    [minP,mini] = min(P);    r = R(:,mini)';    %  put back the second representative of each complex quadruple    l = length(r);    for i = 1:l	if (imag(r(i)) ~= 0)	    r = [r conj(r(i))];	end    endend%  construct q = sqrt(Q) from selected roots%  normalize phase so that q(0) is realq = poly(r);q0 = q(length(q));q = q*(conj(q0)/abs(q0));% Everything should be real, so drop the imaginary partsq = real(q);% Now compute h by multiplying with (0.5(1+z))^pfor k = 1:p,  q = conv(q,[1/2 1/2]);end% Normalizeh = q/sum(q);%  choose order so that the largest coefficient shows up in the first half[hmax,imax] = max(abs(h));if (imax > length(h)/2)    h = h(length(h):-1:1);end% find g, assemble the resultg = h(length(h):-1:1);g(2:2:end) = - g(2:2:end);S = mpoly(reshape([h;g],2,1,length(h)),0,'symbol',2,1);returnfunction P = psi_tot(r)% PSI_TOT -- maximum deviation from linear phase for given choice of roots%%        P = psi_tot(r)%        % This is used to find the most symmetric Daubechies wavelets.%% See page 505 in%%        Ingrid Daubechies%        Orthonormal Bases of Compactly Supported Wavelets II: Variations on a Theme%        Siam J. Math. Anal. vol. 24, no. 2, March 1993%        p. 499 - 519npoints = 65;xi = (0:npoints-1)/(npoints-1) * 2 * pi;Psi = zeros(1,npoints);for j = 1:length(r)    if (imag(r(j)) == 0)	temp = atan((1+r(j))/(1-r(j))*tan(xi/2));    else	Rl = abs(r(j));	alphal = angle(r(j));	temp = atan((1 - Rl^2)*sin(xi)./((1+Rl^2)*cos(xi)-2*Rl*cos(alphal)));    end	    %  get rid of jumps in arctangent    for k = 2:npoints	if (temp(k) - temp(k-1) > pi/2)	    temp(k:npoints) = temp(k:npoints) - pi;	end	if (temp(k) - temp(k-1) < -pi/2)	    temp(k:npoints) = temp(k:npoints) + pi;	end    end    temp = temp - xi/(2*pi) * temp(npoints);    Psi = Psi + temp;endP = max(abs(Psi));returnfunction [H,Ht] = bidaubechies(m1,m2,roots1)% BIDAUBECHIES --  coefficients of symmetric biorthogonal Daubechies wavelet%%        [H,Ht] = bidaubechies(m1,m2,roots)%% Calculates the coefficients for the biorthogonal symmetric% Daubechies wavelets with m1 coefficients for H, m2 coefficients for% Ht (m1 + m2 = divisible by 4), as described on p. 278 of "Ten% Lectures on Wavelets" (TLW). The total number of vanishing moments% between F and Ft is (m1+m2)/2.%% Algorithm: Form the polynomial Q(z) described in "Ten Lectures on% Wavelets" (TLW). It is called p_A there (page 172). This polynomial% has roots that come in real pairs (r, 1/r) and complex quadruples% (z, z_bar, 1/z, 1/z_bar).%% For orthogonal wavelets (m1 = m2 = 2m), we pick one real root% from each pair, and one complex conjugate pair from each complex% quadruple to get the factor polynomials, and add one factor of% (1+z)^m to each.%% In the present setting, we need to assign each real pair and complex% quadruple entirely to one polynomial or the other, and we can split% the total factor (1+z)^(m1+m2) between them any way we want.%% If m=(m1+m2)/4, then at least up to m=10, we have 0 real pairs if m% is odd, 1 real pair if m is even, the rest are complex% quadruples. We always assign the real pair to H (otherwise, just% switch H, Ht). The complex pairs with subscripts given in the% subscript vector ROOTS also get put into F. Then we adjust the (1+z)% factors to get the correct lengths.%% I cannot guarantee that this routine will work for m > 10.% error checking on argumentsif (nargin < 3)    error('usage: [S,St] = bidaubechies(m1,m2,roots)');endm = (m1 + m2)/4;if (round(m) ~= m)    error('m1 + m2 must be divisible by 4');endif (m1 <= 0 | m2 <= 0)    error('m1, m2 must be >= 1');endncq = floor((m-1)/2);  % number of complex quadruplesif (max(roots1) > ncq)    error(['you cannot pick more than ',num2str(ncq),' complex roots']);endl = (ncq - length(roots1)); % number of quadruples used in q2n2 = m2 - (l * 4 + 1);n1 = 2*m - n2;if (n1 < 0 | n2 < 0)    error(['for selected roots, m2 must be between ',num2str(l*4+1),...	' and ',num2str(2*m+l*4+1)]);end%  Compute polynomial P = P_m(y) (eq. 6.1.12 in TLW)k = 0:m-1;P = mpoly(reshape(binomial(m-1+k,k),1,1,m));%  Convert P_m(y), y = sin^2(w/2) to form Q(z), z = exp(iw)y = mpoly({-1/4,1/2,-1/4},-1);Q = P(y);%  Find the roots of Q, sort into real pairs and complex quadruplesr = roots(Q.coef(:));rr = r(find(abs(r) > 1 & imag(r) == 0));rc = r(find(abs(r) > 1 & imag(r) > 0));% select the desired complex quadruplesrc1 = rc(roots1);roots2 = 1:length(rc);roots2 = roots2(~ismember(roots2,roots1));rc2 = rc(roots2);% put back the other representatives of each real pair or complex quadruplerr = [rr; 1./rr];rc1 = [rc1; 1./rc1; conj(rc1); 1./conj(rc1)];rc2 = [rc2; 1./rc2; conj(rc2); 1./conj(rc2)];% construct q1, q2 from selected roots% by construction, they should both be real% zero any complex components introduced by roundoffq1 = real(poly([rr;rc1]));q2 = real(poly(rc2));% Multiply with powers of (0.5(1+z))for k = 1:n1  q1 = conv(q1,[1/2 1/2]);endfor k = 1:n2  q2 = conv(q2,[1/2 1/2]);end% Normalizeh  = q1 / sum(q1);ht = q2 / sum(q2);% find dualsg = ht(length(ht):-1:1);g(2:2:end) = - g(2:2:end);gt = h(length(h):-1:1);gt(1:2:end) = - gt(1:2:end);% adjust h, ht to common centerH = mpoly(reshape(h,1,1,length(h)),-(length(h)-1)/2,'symbol',2,1);Ht = mpoly(reshape(ht,1,1,length(ht)),-(length(ht) - 1)/2,'symbol',2,1);% H = mpoly(reshape(h,1,1,length(h)),0,'symbol',2,1);% Ht = mpoly(reshape(ht,1,1,length(ht)),(length(h) - length(ht))/2,'symbol',2,1);% put result togetherP = polyphase(H);Pt = polyphase(Ht);P = [P;Pt(1,2)',-Pt(1,1)'];Pt = [Pt;P(1,2)',-P(1,1)'];H = symbol(P);Ht = symbol(Pt);function [H,Ht] = cohen(n,ntilde)% COHEN -  coefficients for Cohen biorthogonal wavelets%%        [H,Ht] = cohen(n,ntilde)%  % Returns the wavelet coefficients for the wavelets introduced on% page 540 in %  %       Cohen - Daubechies - Feauveau%       Biorthogonal Bases of Compactly Supported Wavelete%       Comm. Pure Appl., Math 45 (1992), p. 485 - 560%       % n and ntilde are integers, with ntilde >= 1, n + ntilde even%  check argumentsif (ntilde < 1)    error('cohen: ntilde must be >= 1');endif (~ iseven(n + ntilde))    error('cohen: n + ntilde must be even');endif (iseven(n))    k = 0;else    k = 1;end%  h coefficients%  these are just binomials, i.e. phi is a B-splineh = binomial(n,0:n) / 2^n;h = reshape(h,1,1,length(h));hmin = (k - n)/2;h = mpoly(sym(h),hmin);%  g coefficientsz = mpoly(sym(1),1);term1 = ((1-z)/2)^ntilde;L = (n + ntilde)/2;PL = cell(1,L);for i = 0:L-1    PL{i+1} = binomial(L-1+i,i);endPL = mpoly(PL);term2 = PL(mpoly({1/4,1/2,1/4},-1));g = term1 * term2;l = (2 - k - ntilde)/2;g = (-1)^(l+1) * g;g.min = g.min + l; H = [h;g];H.type = 'symbol';H.r = 1;H.m = 2;%  htilde, gtilde coefficientsP = polyphase(H);Pt = longinv(P');Ht = symbol(Pt);    function l = iseven(x)% ISEVEN -- check whether an integer is even or odd%  %        l = iseven(x)% % returns 1 = true   if x is an even integer,%         0 = false  otherwiseif (x == 2 * round(x/2))    l = 1;else    l = 0;end

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