xmx.java

java写的一交通导航程序点击任意两站点就可以以可视化的方式将转车次数最少的乘车方案找出来 注：连ACCESS数据库 odbc数据源名称为lv

import java.awt.*;
import java.awt.image.*;

public class xmx implements Runnable//显示站点
{     
	BufferedImage buf;
	int width,height;
	Thread 	newThread;
	Point point;
	String name;
	int index;
	Graphics2D bufg;
	draw1 draw;
	int timer;
	boolean active=false; 
	public xmx(draw1 d,String str,all a)
	{       
		name=str;
		draw=d;
		int i;
		for(i=0;i<a.num;i++){
			if(a.name[i].equals(name)) break;
		}
		index=i;
		point=a.point[index];
		buf=new BufferedImage(200,100,BufferedImage.TYPE_INT_ARGB);
		bufg=buf.createGraphics();
		timer=0;
		draw.px=400-point.x;
		draw.py=384-point.y;
		if(draw.px>=0) 	draw.px=0;//控制拖动的范围
        if((int)(draw.scale*draw.px)<=(974-(int)(draw.width*draw.scale)))
        			draw.px=974-(int)(draw.width*draw.scale);
        if(draw.py>=0)	draw.py=0;
        if((int)(draw.scale*draw.py)<=(768-(int)(draw.height*draw.scale)))
        		draw.py=768-(int)(draw.height*draw.scale);
		new Thread(this).start();
	}
	public void run()
	{
		active=true;
		int x=0;
		int y=0;
		bufg.setBackground(new Color(0,0,0,0));
		bufg.setColor(Color.red);
		bufg.setFont(new Font("fs",Font.BOLD,14));
		while(timer<50){
			bufg.clearRect(0,0,200,100);
			x=x+2;
			y=y+1;
			bufg.drawRect(x,y,200-2*x,100-2*y);
			draw.repaint();
			timer++;
			try {Thread.sleep(30);}catch(Exception ee){}
		}
		for(int i=0;i<20;i++){
			bufg.clearRect(0,0,200,100);
			bufg.setColor(Color.green);
			bufg.fillOval(96,41,10,10);
			
			bufg.drawString(name,60,80);
			draw.repaint();
			try {Thread.sleep(200);}catch(Exception ee){}
			bufg.clearRect(0,0,200,100);
			bufg.setColor(Color.red);
			bufg.fillOval(96,40,13,13);			
			bufg.drawString(name,60,80);
			draw.repaint();
			try {Thread.sleep(200);}catch(Exception ee){}
			
		}
		active=false;
		draw.repaint();	
	}
}