find.m

matlab数字信号处理工具箱

function list = find(varargin)
% XMLTREE/FIND Find elements in a tree with specified characteristics
% FORMAT list = find(varargin)
%
% tree  - XMLTree object
% xpath - string path with specific grammar (XPath)
% uid   - lists of root uid's
% parameter/value - pair of pattern
% list  - list of uid's of matched elements
%
%      list = find(tree,xpath)
%      list = find(tree,parameter,value[,parameter,value])
%      list = find(tree,uid,parameter,value[,parameter,value])
%
% Grammar for addressing parts of an XML document: 
%        XML Path Language XPath (http://www.w3.org/TR/xpath)
% Example: /element1//element2[1]/element3[5]/element4
%_______________________________________________________________________
%
% Find elements in an XML tree with specified characteristics or given
% a path (using a subset of XPath language).
%_______________________________________________________________________
% @(#)find.m                 Guillaume Flandin                 01/10/29

% TODO:
%   - clean up subroutines
%   - find should only be documented using XPath (other use is internal)
%   - handle '*', 'last()' in [] and '@'
%   - if a key is invalid, should rather return [] than error ?

if nargin==0
	error('[XMLTree] A tree must be provided');
elseif nargin==1
	list = 1:length(tree.tree);
	return
elseif mod(nargin,2)
	list = sub_find_subtree1(varargin{1}.tree,root(tree),varargin{2:end});
elseif isa(varargin{2},'double') & ...
	   ndims(varargin{2}) == 2 & ...
	   min(size(varargin{2})) == 1
	list = unique(sub_find_subtree1(varargin{1}.tree,varargin{2:end}));
elseif nargin==2 & ischar(varargin{2})
	list = sub_pathfinder(varargin{:});
else
   error('[XMLTree] Arguments must be parameter/value pairs.');
end

%=======================================================================
function list = sub_find_subtree1(varargin)
	list = [];
	for i=1:length(varargin{2})
		res = sub_find_subtree2(varargin{1},...
				varargin{2}(i),varargin{3:end});
		list = [list res];
	end

%=======================================================================
function list = sub_find_subtree2(varargin)
	uid = varargin{2};
	list = [];
	if sub_comp_element(varargin{1}{uid},varargin{3:end})
		list = [list varargin{1}{uid}.uid];
	end
	if isfield(varargin{1}{uid},'contents')
		list = [list sub_find_subtree1(varargin{1},...
		        varargin{1}{uid}.contents,varargin{3:end})];
	end

%=======================================================================
function match = sub_comp_element(varargin)
match = 0;
try,
	% v = getfield(varargin{1}, varargin{2}); % slow...
	for i=1:floor(nargin/2)
		v = subsref(varargin{1}, struct('type','.','subs',varargin{i+1}));     
		if strcmp(v,varargin{i+2})
			match = 1;
		end
	end
catch,
end

% More powerful but much slower
%match = 0;
%for i=1:length(floor(nargin/2)) % bug: remove length !!!
%   if isfield(varargin{1},varargin{i+1})
%	  if ischar(getfield(varargin{1},varargin{i+1})) & ischar(varargin{i+2})
%	   if strcmp(getfield(varargin{1},varargin{i+1}),char(varargin{i+2}))
%			match = 1;
%		 end
%	  elseif isa(getfield(varargin{1},varargin{i+1}),'double') & ...
%			isa(varargin{i+2},'double')
%		 if getfield(varargin{1},varargin{i+1}) == varargin{i+2}
%			match = 1;
%		end
%	 else 
%		warning('Cannot compare different objects');
%	  end
%   end
%end

%=======================================================================
function list = sub_pathfinder(tree,pth)
	%- Search for the delimiter '/' in the path
	i = findstr(pth,'/');
	%- Begin search by root
	list = root(tree);
	%- Walk through the tree
	j = 1;
	while j <= length(i)
		%- Look for recursion '//'
		if j<length(i) & i(j+1)==i(j)+1
			recursive = 1;
			j = j + 1;
		else
			recursive = 0;
		end
		%- Catch the current tag 'element[x]'
		if j ~= length(i)
			element = pth(i(j)+1:i(j+1)-1);
		else
			element = pth(i(j)+1:end);
		end
		%- Search for [] brackets
		k = xml_findstr(element,'[',1,1);
		%- If brackets are present in current element
		if ~isempty(k)
			l   = xml_findstr(element,']',1,1);
			val = str2num(element(k+1:l-1));
			element = element(1:k-1);
		end
		%- Use recursivity
		if recursive
			list = find(tree,list,'name',element);
		%- Just look at children
		else
			if i(j)==1 % if '/root/...' (list = root(tree) in that case)
				if sub_comp_element(tree.tree{list},'name',element)
					% list = 1; % list still contains root(tree)
				else
					list = [];
					return;
				end
			else
				list = sub_findchild(tree,list,element);
			end
		end
		% If an element is specified using a key
		if ~isempty(k)
			if val < 1 | val > length(list)+1
				error('[XMLTree] Bad key in the path.');
			elseif val == length(list)+1
				list = [];
				return;
			end
			list = list(val);
		end
		if isempty(list), return; end
		j = j + 1;
	end
	
%=======================================================================
function list = sub_findchild(tree,listt,elmt)
	list = [];
	for a=1:length(listt)
		for b=1:length(tree.tree{listt(a)}.contents)
			if sub_comp_element(tree.tree{tree.tree{listt(a)}.contents(b)},'name',elmt)
				list = [list tree.tree{tree.tree{listt(a)}.contents(b)}.uid];
			end
		end
	end