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Date: Wed, 13 Nov 1996 23:15:08 GMT
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<HEAD><TITLE>Homework #1 Solutions</TITLE></HEAD><BODY><h2>Solutions to Homework #1</H2><p><p> <b> Question 2.1</b> Cost effectiveness is performance per dollar of cost,and the performance will depend on the workload choice.<P>Cost effectiveness can be measured in the numbers of executions per secondper dollar of machine cost:<P>executions per second per dollar = <IMG  ALIGN=MIDDLE ALT="" SRC="img1.gif">  <BR><P>executions per second per dollar for S1  = <IMG  ALIGN=MIDDLE ALT="" SRC="img2.gif"> <BR><P>executions per second per dollar for S2 dollars = <IMG  ALIGN=MIDDLE ALT="" SRC="img3.gif"> <BR><P>So System 2 is more cost effective.  By a ratio of  <IMG  ALIGN=MIDDLE ALT="" SRC="img4.gif"><P><hr><b> Question 2.2</b> We can use the same method as the previous part, butthe execution time is the sum of the two execution times.<P>executions per second per dollar for S1 = <IMG  ALIGN=MIDDLE ALT="" SRC="img5.gif"> <BR><P>executions per second per dollar for S2 = <IMG  ALIGN=MIDDLE ALT="" SRC="img6.gif"> <BR><P>So System 1 is slightly more cost effective, by a factor of<IMG  ALIGN=MIDDLE ALT="" SRC="img7.gif"> <BR><P><hr><b> Question 2.3</b> We do this problem by finding the amount of time thatprogram 2 can be run in an hour and using that for executions per second,the throughput measure.<P>executions of P2 per hour = <IMG  ALIGN=MIDDLE ALT="" SRC="zz1.gif"><BR><P>executions of P2 per hour on S1 = <IMG  ALIGN=MIDDLE ALT="" SRC="zz2.gif"><BR><P>executions of P2 per hour on S2 = <IMG  ALIGN=MIDDLE ALT="" SRC="zz3.gif"><BR><P>Hence we can conclude that S2 has higher throughput. <BR><P>Cost per run per hour for P2 in dollars: <BR><P>For S1 =  <IMG  ALIGN=MIDDLE ALT="" SRC="zz4.gif"> = 18.76 <BR><P>For S2 =  <IMG  ALIGN=MIDDLE ALT="" SRC="zz5.gif"> = 23.07 <BR><P>Hence S1 is more cost effective for this workload.  <BR><P> <hr><b> Question 2.27</b><P><IMG  ALIGN=MIDDLE ALT="" SRC="img11.gif"> <BR><P>Harmonic Mean (HM) = <IMG  ALIGN=MIDDLE ALT="" SRC="img12.gif"> <BR><P>mean of times = <IMG  ALIGN=MIDDLE ALT="" SRC="img13.gif"><BR><P>mean of times = <IMG  ALIGN=MIDDLE ALT="" SRC="img14.gif"><BR><P>Therefore, HM = <IMG  ALIGN=MIDDLE ALT="" SRC="img15.gif"><BR><P><hr><b> State machine</b><P>A <a href="match.ps">schematic</a> of a possible solution to the statemachine problem.The <a href="sim.ps">waveform</a> of the simulation of this schematic.<p><BR> <HR><P><ADDRESS><I>Course Account ece552 <BR>Thu Sep 12 15:55:17 CDT 1996</I></ADDRESS></BODY>

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