📄 romberg.m
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#include "iostream"
#include "cmath"
#include "iomanip"
using namespace std;
#define N 20
#define e 1E-10
typedef double TYPE;
TYPE f(TYPE x) {
if (x==0) return 1.0;
return sin(x)/x;
}
double T2n(double a,double b,int n=0,double Tn=0) {
double New=0;
double h;
if (n==0) {
h = b-a;
return (f(a)+f(b))*h/2;
}
h = (b-a)/n;
double x = a+h/2;
while (x New += f(x);
x += h;
}
return (Tn+h*New)/2;
}
double Romberg(double a,double b) {
double T1,T2,S1,S2,C1,C2,R1,R2;
int k = 0,n=1;
cout< cout<<"k "<<"T "<<" S "<<" C "<<" R "< T1 = T2n(0,1);
cout< do {k++;
T2 = T2n(0,1,n,T1);
cout< S2 = (4*T2-T1)/3;
cout< if (k!=1) {
C2 = (16*S2-S1)/15;
cout< if (k!=2) {
R2 = (64*C2-C1)/63;
cout< if (k!=3 && fabs(R2-R1) cout<<"\n\n迭代次数: "< return R2;
}
R1=R2;
}
C1=C2;
}
S1=S2;
T1 = T2;
n*=2;
// k++;
cout< }while (k if (k==N) cout<<"\n迭代超过次数!!!\n"< return 0;
}
int main ()
{
cout< <<"最终结果为: "
< return 1;
}
求得是f(x)=sin(x)/x从0-1上的积分
Romberg
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