📄 产生gold序列程序.m
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% MATLAB script for Illustrative Problem 5, Chapter 9.echo on% first determine the maximal length shift register sequences% We'll take the initial shift register content as "00001".connections1=[1 0 1 0 0];connections2=[1 1 1 0 1];sequence1=ss_mlsrs(connections1);sequence2=ss_mlsrs(connections2);% cyclically shift the second sequence and add it to the first oneL=2^length(connections1)-1;;for shift_amount=0:L-1, temp=[sequence2(shift_amount+1:L) sequence2(1:shift_amount)]; gold_seq(shift_amount+1,:)=(sequence1+temp) - floor((sequence1+temp)./2).*2; echo off ;end;echo on ;% find the max value of the cross correlation for these sequencesmax_cross_corr=0;for i=1:L-1, for j=i+1:L, % equivalent sequences c1=2*gold_seq(i,:)-1; c2=2*gold_seq(j,:)-1; for m=0:L-1, shifted_c2=[c2(m+1:L) c2(1:m)]; corr=abs(sum(c1.*shifted_c2)); if (corr>max_cross_corr), max_cross_corr=corr; end; echo off ; end; end;end;% note that max_cross_corr turns out to be 9 in this example...
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