📄 isfeasible.m
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function result = isfeasible(a,b)
% Determine whether or not the intersection of two linear constraint objects
% exists.
%
% Syntax:
% "C = isfeasible(a,b)"
%
% Description:
% "isfeasible(a,b)" returns a "0" if the intersection of "a" and "b" is
% empty, otherwise, "isfeasible(a,b)" returns "1".
%
% Examples:
% Given two linear constraint objects, "a" representing a square in the
% x3 = 0 plane with corners at (x1,x2) pairs (2,1), (2,3), (4,3), and
% (4,1) and "b", another square in the same plane with corners at (2,1),
% (2,2), (3,1), and (3,2),
%
%
%
% "C = isfeasible(a,b)"
%
%
%
% returns "1".
%
% See Also:
% linearcon,and
if isa(b,'polyhedron')
b = linearcon(b);
end
if isa(b,'linearcon')
c = intersect(a,b,0);
else
c = linearcon;
end
result = ~isempty(c);
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