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📄 assert_l.m

📁 linear time-frequency toolbox
💻 M
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function [b,N,L]=assert_L(Lin,Lwindow,a,M,callfun)%ASSERT_L  Validate lattice and window size.%   Usage:  [b,N,L]=assert_L(Lin,Lwindow,a,M,callfun);%%   Input parameters:%         Lin     : Length of signal (see below).%         Lwindow : Length of window.%         a       : Length of time shift.%         M       : Number of modulations.%         callfun : Name of calling function.%         flag    : See below.%   Output parameters:%         b       : Length of frequency shift.%         N       : Number of translations.%         L       : Transform length.         %%  Calculate a minimal transform length, or verify a user specified%  input length.%%  The routine assumes that a and M has already been checked. use%  asser_squarelat for this.%%  Lin takes the following values:%      positive : This is a value of L specified by the user%      negative : This is the length of the signal. A minimal value of%                 L is returned.%%  Set Lwindow to 0 if window length is not to be checked.%  if (prod(size(Lin))~=1 || ~isnumeric(Lin))  error([callfun,': L must be a scalar']);end;if rem(Lin,1)~=0  error([callfun,': L must be an integer']);end;% This test should not be placed here, it gets called to often.% However, this is an easy place to put it.%% Length of window must be dividable by M.% We cannot automically zero-extend the window, as it can% possible break some symmetry properties of the window, and we don't% know which symmetries to preserve.if rem(Lwindow,M)~=0  error([callfun,': Length of window must be dividable by M.']);end;if Lin<0  % Smallest length transform.  Lsmallest=lcm(a,M);  % Choose a transform length larger than both the length of the  % signal and the window.  L=ceil(max(-Lin,Lwindow)/Lsmallest)*Lsmallest;else  L=Lin;  if rem(L,M)~=0    error([callfun,': The length of the transform must be divisable by M=',num2str(M)]);  end;  if rem(L,a)~=0    error([callfun,': The length of the transform must be divisable by a=',num2str(a)]);  end;  if rem(L,a)~=0    error([callfun,': The length of the transform must be divisable by a=',num2str(a)]);  end;  end;b=L/M;N=L/a;

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