📄 form1.frm
字号:
VERSION 5.00
Begin VB.Form Form1
Caption = "Form1"
ClientHeight = 5415
ClientLeft = 60
ClientTop = 450
ClientWidth = 9525
LinkTopic = "Form1"
ScaleHeight = 5415
ScaleWidth = 9525
StartUpPosition = 3 '窗口缺省
Begin VB.CommandButton Command1
Caption = "Command1"
Height = 435
Left = 3255
TabIndex = 0
Top = 4620
Width = 1065
End
Begin VB.Timer Timer1
Interval = 100
Left = 315
Top = 525
End
End
Attribute VB_Name = "Form1"
Attribute VB_GlobalNameSpace = False
Attribute VB_Creatable = False
Attribute VB_PredeclaredId = True
Attribute VB_Exposed = False
Option Explicit
Const D = 100 '方格的宽度
Const BT = 3000 '跑道底部的y坐标
Dim l1(22) As Integer '每层跑道左边有几个方块
Dim l2(22) As Integer '每层跑道右边有几个方块
Dim cx As Single '赛车的在x轴的位置
Dim cy As Single
Dim i As Integer
Private Sub Command1_Click()
cx = Width / 2 - 3 * D / 2
cy = Height - D
drawcar
For i = 1 To 20
l1(i) = 0
l2(i) = 0
drawway (i)
Next i
Timer1.Enabled = True
End Sub
Private Sub drawcar()
Line (cx, BT - 100)-Step(3 * D, D), BackColor, BF
Line (cx + D, BT - 200)-Step(D, D), BackColor, BF '先擦
Line (cx, BT - 100)-Step(3 * D, D), RGB(225, 0, 0), BF
Line (cx + D, BT - 200)-Step(D, D), RGB(225, 0, 0), BF
End Sub
Private Sub drawway(n)
Line (Width / 2 - 3 * D / 2 - 2 * D, BT - n * D)-Step(7 * D, D), BackColor, BF '先擦后画
Line (Width / 2 - 3 * D / 2 - 2 * D, BT - n * D)-Step(l1(n) * D, D), , BF
Line (Width / 2 - 3 * D / 2 + 5 * D, BT - n * D)-Step(-l2(n) * D, D), , BF
End Sub
Private Sub Form_KeyPress(KeyAscii As Integer)
Select Case KeyAscii
Case Asc("a"), Asc("A")
cx = cx - D
Case Asc("s"), Asc("S")
cx = cx + D
End Select
End Sub
Private Sub Timer1_Timer()
Randomize
For i = 1 To 19
l1(i) = l1(i + 1)
l2(i) = l2(i + 1)
drawway (i)
Next i
Do
l1(20) = Int(Rnd * 5)
l2(20) = Int(Rnd * 5)
Loop Until ((l1(20) + l2(20) <= 4) And (l1(20) - l1(19) <= 1) And _
(l2(20) - l2(19) <= 1) And (l1(19) + l2(20) <= 4) And _
(l1(20) + l2(19) <= 4)) '这里生成新一层跑道,
'注意要筛去玩家不可能通过的情况!
drawway (20)
'以上画出跑道
drawcar
test
End Sub
Private Sub test()
If 3.5 * D - Width / 2 + cx < l1(1) * D Then Timer1.Enabled = False
If 3.5 * D - Width / 2 + cx + D < l1(2) * D Then Timer1.Enabled = False
If 3.5 * D - (cx + 3 * D - Width / 2) < l2(1) * D Then Timer1.Enabled = False
If 3.5 * D - (cx + 2 * D - Width / 2) < l2(2) * D Then Timer1.Enabled = False
End Sub
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