📄 16.cpp
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/*---------------------------------------例题16-------------------------------------------------------------------*/
#include <iostream>
using namespace std;
int main()
{
int m, n;
cout<<"Please input the two numbers:"<<endl;
cin>>m>>n;
cout<<"m = "<<m<<'\t'<<"n = "<<n<<endl;
int store = m * n;//若求出了最大公约数,最小公倍数就很好求了.
while(m>0)
{
if(n>m)
{
int temp = m;
m = n;
n = temp;
}
m -= n;
}
cout<<"The greatest common divisor of the two numbers is: "<<n<<endl;
cout<<"The lease common multiple of the two numbers is: "<<store/n<<endl;
return 0;
}
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