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📄 md4.c

📁 这是一个同样来自贝尔实验室的和UNIX有着渊源的操作系统, 其简洁的设计和实现易于我们学习和理解
💻 C
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#include "os.h"#include <libsec.h>/* *  This MD4 is implemented from the description in Stinson's Cryptography, *  theory and practice. -- presotto *//* *	Rotate ammounts used in the algorithm */enum{	S11=	3,	S12=	7,	S13=	11,	S14=	19,	S21=	3,	S22=	5,	S23=	9,	S24=	13,	S31=	3,	S32=	9,	S33=	11,	S34=	15,};typedef struct MD4Table MD4Table;struct MD4Table{	uchar	x;	/* index into data block */	uchar	rot;	/* amount to rotate left by */};static MD4Table tab[] ={	/* round 1 *//*[0]*/	{ 0,	S11},		{ 1,	S12},		{ 2,	S13},		{ 3,	S14},		{ 4,	S11},		{ 5,	S12},		{ 6,	S13},		{ 7,	S14},		{ 8,	S11},		{ 9,	S12},		{ 10,	S13},		{ 11,	S14},		{ 12,	S11},		{ 13,	S12},		{ 14,	S13},		{ 15,	S14},	/* round 2 *//*[16]*/{ 0,	S21},		{ 4,	S22},		{ 8,	S23},		{ 12,	S24},		{ 1,	S21},		{ 5,	S22},		{ 9,	S23},		{ 13,	S24},		{ 2,	S21},		{ 6,	S22},		{ 10,	S23},		{ 14,	S24},		{ 3,	S21},		{ 7,	S22},		{ 11,	S23},		{ 15,	S24},	/* round 3 *//*[32]*/{ 0,	S31},		{ 8,	S32},		{ 4,	S33},		{ 12,	S34},		{ 2,	S31},		{ 10,	S32},		{ 6,	S33},		{ 14,	S34},		{ 1,	S31},		{ 9,	S32},		{ 5,	S33},		{ 13,	S34},		{ 3,	S31},		{ 11,	S32},		{ 7,	S33},		{ 15,	S34},	};static void encode(uchar*, u32int*, ulong);static void decode(u32int*, uchar*, ulong);static voidmd4block(uchar *p, ulong len, MD4state *s){	int i;	u32int a, b, c, d, tmp;	MD4Table *t;	uchar *end;	u32int x[16];	for(end = p+len; p < end; p += 64){		a = s->state[0];		b = s->state[1];		c = s->state[2];		d = s->state[3];		decode(x, p, 64);			for(i = 0; i < 48; i++){			t = tab + i;			switch(i>>4){			case 0:				a += (b & c) | (~b & d);				break;			case 1:				a += ((b & c) | (b & d) | (c & d)) + 0x5A827999;				break;			case 2:				a += (b ^ c ^ d) + 0x6ED9EBA1;				break;			}			a += x[t->x];			a = (a << t->rot) | (a >> (32 - t->rot));				/* rotate variables */			tmp = d;			d = c;			c = b;			b = a;			a = tmp;		}		s->state[0] += a;		s->state[1] += b;		s->state[2] += c;		s->state[3] += d;		s->len += 64;	}}MD4state*md4(uchar *p, ulong len, uchar *digest, MD4state *s){	u32int x[16];	uchar buf[128];	int i;	uchar *e;	if(s == nil){		s = malloc(sizeof(*s));		if(s == nil)			return nil;		memset(s, 0, sizeof(*s));		s->malloced = 1;	}	if(s->seeded == 0){		/* seed the state, these constants would look nicer big-endian */		s->state[0] = 0x67452301;		s->state[1] = 0xefcdab89;		s->state[2] = 0x98badcfe;		s->state[3] = 0x10325476;		s->seeded = 1;	}	/* fill out the partial 64 byte block from previous calls */	if(s->blen){		i = 64 - s->blen;		if(len < i)			i = len;		memmove(s->buf + s->blen, p, i);		len -= i;		s->blen += i;		p += i;		if(s->blen == 64){			md4block(s->buf, s->blen, s);			s->blen = 0;		}	}	/* do 64 byte blocks */	i = len & ~0x3f;	if(i){		md4block(p, i, s);		len -= i;		p += i;	}	/* save the left overs if not last call */	if(digest == 0){		if(len){			memmove(s->buf, p, len);			s->blen += len;		}		return s;	}	/*	 *  this is the last time through, pad what's left with 0x80,	 *  0's, and the input count to create a multiple of 64 bytes	 */	if(s->blen){		p = s->buf;		len = s->blen;	} else {		memmove(buf, p, len);		p = buf;	}	s->len += len;	e = p + len;	if(len < 56)		i = 56 - len;	else		i = 120 - len;	memset(e, 0, i);	*e = 0x80;	len += i;	/* append the count */	x[0] = s->len<<3;	x[1] = s->len>>29;	encode(p+len, x, 8);	/* digest the last part */	md4block(p, len+8, s);	/* return result and free state */	encode(digest, s->state, MD4dlen);	if(s->malloced == 1)		free(s);	return nil;}/* *	encodes input (u32int) into output (uchar). Assumes len is *	a multiple of 4. */static voidencode(uchar *output, u32int *input, ulong len){	u32int x;	uchar *e;	for(e = output + len; output < e;) {		x = *input++;		*output++ = x;		*output++ = x >> 8;		*output++ = x >> 16;		*output++ = x >> 24;	}}/* *	decodes input (uchar) into output (u32int). Assumes len is *	a multiple of 4. */static voiddecode(u32int *output, uchar *input, ulong len){	uchar *e;	for(e = input+len; input < e; input += 4)		*output++ = input[0] | (input[1] << 8) |			(input[2] << 16) | (input[3] << 24);}

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