📄 diagmeet.note
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Here is a comparison matrix which shows a case in whichit is possible for the forward and backward scan in `diag'to meet along a nonzero length of diagonal simultaneous(so that bdiag[d] and fdiag[d] are not equal)even though there is no snake on that diagonal at the meeting point. 85 1 1 1 159 1 1 17 1 2 3 460 1 21 2 2 3 471 3 3 4 585 4 3 4 517 5 4 51 6 4 5 6183 7 5 6 710 8 6 71 9 6 7 812 7 8 9 1013 10 8 9 1014 10 9 1017 10 101 10 9 101 8 10 10 10183 8 7 9 9 910 7 6 8 9 8 81 6 5 7 71 5 6 61 5 5 550 5 4 4 41 4 3 385 5 4 3 2 21 2 117 5 4 3 2 1 11 1 0 85 1 1 1 159 1 1 17
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