1007.cpp

zju 1007 Numerical Summation of a Series http://acm.zju.edu.cn/show_problem.php?pid=1007

//http://acm.zju.edu.cn/show_problem.php?pid=1007
#include<stdio.h>
#include<math.h>
int main()
{
	double sum,a,k;
	for(a=0.000;a<=2.000;a=a+0.001)
	{
		sum=0; 
		for(k=1;k<14000;k++)
		{
			sum=sum+(1-a)/(k*(k+1)*(k+a));
		}
		sum=sum+(1-a)/(2*14000*14000)+1; 
		printf("%5.3f %16.12f\n", a, sum ); 
	}
	return 0; 
}