📄 c_jiami.c
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//原作者:Niti的朋友
//来源Niti Cheung
//电邮:Niti@hotmail.it
//Blog:www.naio.net
//日期:2003-3-16
//请保留版权
//此代码为免费代码,您可以保留版权的情况下,在教学和演示甚至无限制编译此程序
#include <stdio.h>
#define MAX_KEY 19 //密码变换后的长度
int main(void)
{
char FileName[40];
FILE *inf_file, *newfile;
char buffer;
char Key[MAX_KEY]; //存储密码的字符数组
char B[32]; //定义新数组用于转储
char C[10]; //存储经M序列变换后得到的生成序列
char SwitchTab[256] = {
0xc6, 0x37, 0x87, 0x47,0xdf, 0x46, 0x6,0xac,0xf3,0xe0, 0x86, 0x42, 0x1f, 0x8d, 0x4a, 0x97,
0x5c,0xd8, 0x6c, 0x27, 0x5f, 0x65, 0x84,0xff, 0x2a,0xbd,0xda, 0xa, 0x39,0xba,0xd7,0xfc,
0x8b, 0x2f,0xc9, 0x92, 0x93, 0x3, 0x8f, 0x3c,0xb3,0xaa,0xae,0xef,0xe7, 0x7d,0xe3,0xa1,
0xb0, 0x8c,0xc2,0xcc, 0x71, 0x99,0xa0, 0x59, 0x80,0xd1,0xf8,0xde, 0x4e, 0x82,0xdb,0xa7,
0x60,0xc8, 0x32, 0x51, 0x41, 0x16, 0x55,0xfa,0xd5, 0x43, 0x9d,0xcb, 0x62,0xce, 0x2,0xb8,
0xc5,0xed,0xf0, 0x2e,0xf2, 0x3f,0xeb, 0x45, 0x56, 0x4c, 0x1b, 0x63, 0x54, 0x34, 0x75, 0xc,
0xfd, 0xe, 0x5a, 0x4f,0xc4, 0x24,0xc3,0xa8,0xa4, 0x6f,0xd0, 0x7,0xf5, 0x33, 0x9, 0x7a,
0xe5,0xca,0xf4, 0x8,0xd9, 0x29, 0x73,0xaf, 0x3b, 0x9b, 0x5d,0xe2,0xf1, 0xf,0xcf,0xdd,
0x2c, 0x30,0xc1, 0x3e, 0x5, 0x89,0xb4, 0x81,0xbc, 0x8a, 0x17, 0x23,0xb6, 0x25, 0x61,0xc7,
0xf6,0xe8, 0x4, 0x3d,0xd2, 0x52,0xf9, 0x78, 0x94, 0x1e, 0x7b,0xb1, 0x1d, 0x15, 0x40, 0x4d,
0xfe,0xd3, 0x53, 0x50, 0x64, 0x90,0xb2, 0x35,0xdc,0xcd, 0x3a,0xd6,0xe9,0xa9,0xbe, 0x67,
0x8e, 0x7c, 0x83,0x26, 0x28,0xad, 0x14, 0x6a, 0x36, 0x95,0xbf, 0x5e,0xa6, 0x57, 0x1a, 0x70,
0x5b, 0x77,0xa2, 0x12, 0x31, 0x9a,0xbb, 0x9c, 0x7e, 0x2d,0xb7, 0x1, 0x44, 0x2b, 0x48, 0x58,
0xf7, 0x13,0xab, 0x96, 0x74,0xc0, 0x9f, 0x10,0xe6,0xa3, 0x85, 0x6b, 0x98,0xec, 0x21, 0x19,
0xee, 0x7f, 0x79,0xe1, 0x66, 0x6d, 0x18,0xb9, 0x49, 0x11, 0x88, 0x6e, 0x1c,0xa5, 0x72, 0xd,
0x38,0xea, 0x68, 0x20, 0xb, 0x9e,0xd4, 0x76,0xe4, 0x69, 0x22, 0x0,0xfb,0xb5, 0x4b, 0x91
}; //置换表
int n; //计数器
char s, y;
char COEF = 0x10; //M序列生成器的系数
char t;
int D, d;
int i, j;
printf("请输入要加密的文件名:");
scanf("%s", FileName);
inf_file = fopen(FileName,"rb");
if (inf_file == NULL)
printf("文件打开失败 请检查文件是否存在或文件名是否输入正确\n");
printf("\n 请输入10位字符密码:");
for(n = 0; n < 10; n++)
scanf( "%c", &Key[n]);
n = 0;
do{
Key[n] = SwitchTab[Key[n]]; //从置换表中对密钥进行简单置换
n++;
}while(n < 10);
for(n = 10; n < 19; n++) // 生成 19字节的密钥长度
Key[n] = (Key[n-10] ^ Key[n-7] ^ Key[n-2] ^ Key[n-1] ^ n) << 3; //运算符优先级问题
s = (COEF & 0x80)? 1 : 0; //提取M序列系数的最高位
COEF = (COEF << 1) | 1; //将其左移与上面s的最低位一起构成9bit
C[0] = 1; //初始化生成序列的第一位 这一位是给定的
//所以c 数组应是10 个而不是 9 个
if ( (newfile = fopen("加密文件.txt", "wb+") ) == NULL)
printf("\n创建文件失败");
while ( fread(&buffer, sizeof(char), 1, inf_file) == 1 )
{
for (n = 0; n < 9; n++) //生成9 位序列
{
y = (Key[16] & 0X80)? 1 : 0; //提出8位密钥的最高位
Key[16] = (Key[16] << 1) | C[n]; //将其左移与上面1bit构成9bit
t = Key[16] & COEF; //M序列的计算 将系数与初始值相乘
t ^= ((t << 1) ^ (t << 2) ^ (t << 3) ^ (t << 4) ^ (t << 5) ^ (t << 6) ^ (t << 7)); //将相乘结果模2加
if (t & 0X80) //提取生成的1bit
C[n + 1] = 1 ^ (y & s); //将结果与先前提取的最高位进行模2运算
else
C[n + 1] = 0 ^ (y & s);
}
D = 2 * 2 * C[1] + 2 * C[2] + C[3];//此处数组位置比题目要求大1是因为将C[0]用于固定常量 1 了
d = 2 * 2 * 2 * C[5] + 2 * 2 * C[6] + 2 * C[7] + C[8];
for (n = 0; n < 16; n++) //将密钥前16字节拷至B数组以方便下面的数据处理
B[n] = Key[n];
for (j = 16,i = 0; i < 16; i++, j++)
B[j] = (B[i] + B[i + 11] + B[i + 13] + B[i + 14]) ; //模28的附加式发生器 (16,5,3,2)
// 经以上循环处理后变换后的密钥部分是从B[16] -- B[31] 而不是B[0] -- B[15]
for (n = 0; n < D; n++) // (钟控:进动D拍)
{
y = (B[16] & 0X80)? 1 : 0; // 先对第一字节的最高位提取并保存
for (j = 16; j < 31; j++) // 然后对后面的各位依次左移1bit 因为是循环移位 最后一个字节并没处理
{
s = (B[j + 1] & 0X80)? 1 : 0;
B[j] = (B[j] << 1) | s;
}
B[31] = (B[31] << 1) | y; // 用前面所存储的最高位对最后一字节进行处理
}
for (j = 16; j < 32; j++) // 右 环 移 d 字 节
B[((j + d) % 16)] = B[j];
B[0] ^= Key[17]; //对密钥的首字节和末字节进行模2处理
B[15] ^= Key[18];
for (j = 0; j < 16; j++)
B[j] = SwitchTab[B[j]]; //对B从置换表进行固定字节的替换
Key[17] = (B[0] & B[1] & B[2] & B[3]) | (B[4] & B[5] & B[6] & B[7]); //重新设置m1和m2的值
Key[18] = (B[8] & B[9] & B[10] & B[11]) | (B[12] & B[13] & B[14] & B[15]);
buffer ^= (Key[17] ^ Key[18]);
if (fwrite(&buffer, sizeof(char), 1, newfile) != 1)
printf("\n文件写入错误");
}
fclose(inf_file);
fclose(newfile);
return 0;
}
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