📄 stringutils.java
字号:
/** * $Revision: 5718 $ * $Date: 2006-10-13 17:18:18 -0700 (Fri, 13 Oct 2006) $ * * Copyright (C) 2004-2006 Jive Software. All rights reserved. * * This software is published under the terms of the GNU Public License (GPL), * a copy of which is included in this distribution. */package org.jivesoftware.util;import java.io.UnsupportedEncodingException;import java.security.MessageDigest;import java.security.NoSuchAlgorithmException;import java.text.BreakIterator;import java.util.*;import java.util.concurrent.ConcurrentHashMap;/** * Utility class to peform common String manipulation algorithms. */public class StringUtils { // Constants used by escapeHTMLTags private static final char[] QUOTE_ENCODE = """.toCharArray(); private static final char[] AMP_ENCODE = "&".toCharArray(); private static final char[] LT_ENCODE = "<".toCharArray(); private static final char[] GT_ENCODE = ">".toCharArray(); private StringUtils() { // Not instantiable. } /** * Replaces all instances of oldString with newString in string. * * @param string the String to search to perform replacements on. * @param oldString the String that should be replaced by newString. * @param newString the String that will replace all instances of oldString. * @return a String will all instances of oldString replaced by newString. */ public static String replace(String string, String oldString, String newString) { if (string == null) { return null; } int i = 0; // Make sure that oldString appears at least once before doing any processing. if ((i = string.indexOf(oldString, i)) >= 0) { // Use char []'s, as they are more efficient to deal with. char[] string2 = string.toCharArray(); char[] newString2 = newString.toCharArray(); int oLength = oldString.length(); StringBuilder buf = new StringBuilder(string2.length); buf.append(string2, 0, i).append(newString2); i += oLength; int j = i; // Replace all remaining instances of oldString with newString. while ((i = string.indexOf(oldString, i)) > 0) { buf.append(string2, j, i - j).append(newString2); i += oLength; j = i; } buf.append(string2, j, string2.length - j); return buf.toString(); } return string; } /** * Replaces all instances of oldString with newString in line with the * added feature that matches of newString in oldString ignore case. * * @param line the String to search to perform replacements on * @param oldString the String that should be replaced by newString * @param newString the String that will replace all instances of oldString * @return a String will all instances of oldString replaced by newString */ public static String replaceIgnoreCase(String line, String oldString, String newString) { if (line == null) { return null; } String lcLine = line.toLowerCase(); String lcOldString = oldString.toLowerCase(); int i = 0; if ((i = lcLine.indexOf(lcOldString, i)) >= 0) { char[] line2 = line.toCharArray(); char[] newString2 = newString.toCharArray(); int oLength = oldString.length(); StringBuilder buf = new StringBuilder(line2.length); buf.append(line2, 0, i).append(newString2); i += oLength; int j = i; while ((i = lcLine.indexOf(lcOldString, i)) > 0) { buf.append(line2, j, i - j).append(newString2); i += oLength; j = i; } buf.append(line2, j, line2.length - j); return buf.toString(); } return line; } /** * Replaces all instances of oldString with newString in line with the * added feature that matches of newString in oldString ignore case. * The count paramater is set to the number of replaces performed. * * @param line the String to search to perform replacements on * @param oldString the String that should be replaced by newString * @param newString the String that will replace all instances of oldString * @param count a value that will be updated with the number of replaces * performed. * @return a String will all instances of oldString replaced by newString */ public static String replaceIgnoreCase(String line, String oldString, String newString, int[] count) { if (line == null) { return null; } String lcLine = line.toLowerCase(); String lcOldString = oldString.toLowerCase(); int i = 0; if ((i = lcLine.indexOf(lcOldString, i)) >= 0) { int counter = 1; char[] line2 = line.toCharArray(); char[] newString2 = newString.toCharArray(); int oLength = oldString.length(); StringBuilder buf = new StringBuilder(line2.length); buf.append(line2, 0, i).append(newString2); i += oLength; int j = i; while ((i = lcLine.indexOf(lcOldString, i)) > 0) { counter++; buf.append(line2, j, i - j).append(newString2); i += oLength; j = i; } buf.append(line2, j, line2.length - j); count[0] = counter; return buf.toString(); } return line; } /** * Replaces all instances of oldString with newString in line. * The count Integer is updated with number of replaces. * * @param line the String to search to perform replacements on. * @param oldString the String that should be replaced by newString. * @param newString the String that will replace all instances of oldString. * @return a String will all instances of oldString replaced by newString. */ public static String replace(String line, String oldString, String newString, int[] count) { if (line == null) { return null; } int i = 0; if ((i = line.indexOf(oldString, i)) >= 0) { int counter = 1; char[] line2 = line.toCharArray(); char[] newString2 = newString.toCharArray(); int oLength = oldString.length(); StringBuilder buf = new StringBuilder(line2.length); buf.append(line2, 0, i).append(newString2); i += oLength; int j = i; while ((i = line.indexOf(oldString, i)) > 0) { counter++; buf.append(line2, j, i - j).append(newString2); i += oLength; j = i; } buf.append(line2, j, line2.length - j); count[0] = counter; return buf.toString(); } return line; } /** * This method takes a string and strips out all tags except <br> tags while still leaving * the tag body intact. * * @param in the text to be converted. * @return the input string with all tags removed. */ public static String stripTags(String in) { if (in == null) { return null; } char ch; int i = 0; int last = 0; char[] input = in.toCharArray(); int len = input.length; StringBuilder out = new StringBuilder((int)(len * 1.3)); for (; i < len; i++) { ch = input[i]; if (ch > '>') { } else if (ch == '<') { if (i + 3 < len && input[i + 1] == 'b' && input[i + 2] == 'r' && input[i + 3] == '>') { i += 3; continue; } if (i > last) { out.append(input, last, i - last); } last = i + 1; } else if (ch == '>') { last = i + 1; } } if (last == 0) { return in; } if (i > last) { out.append(input, last, i - last); } return out.toString(); } /** * This method takes a string which may contain HTML tags (ie, <b>, * <table>, etc) and converts the '<'' and '>' characters to * their HTML escape sequences. * * @param in the text to be converted. * @return the input string with the characters '<' and '>' replaced * with their HTML escape sequences. */ public static String escapeHTMLTags(String in) { if (in == null) { return null; } char ch; int i = 0; int last = 0; char[] input = in.toCharArray(); int len = input.length; StringBuilder out = new StringBuilder((int)(len * 1.3)); for (; i < len; i++) { ch = input[i]; if (ch > '>') { } else if (ch == '<') { if (i > last) { out.append(input, last, i - last); } last = i + 1; out.append(LT_ENCODE); } else if (ch == '>') { if (i > last) { out.append(input, last, i - last); } last = i + 1; out.append(GT_ENCODE); } } if (last == 0) { return in; } if (i > last) { out.append(input, last, i - last); } return out.toString(); } /** * Used by the hash method. */ private static Map<String, MessageDigest> digests = new ConcurrentHashMap<String, MessageDigest>(); /** * Hashes a String using the Md5 algorithm and returns the result as a * String of hexadecimal numbers. This method is synchronized to avoid * excessive MessageDigest object creation. If calling this method becomes * a bottleneck in your code, you may wish to maintain a pool of * MessageDigest objects instead of using this method. * <p/> * A hash is a one-way function -- that is, given an * input, an output is easily computed. However, given the output, the * input is almost impossible to compute. This is useful for passwords * since we can store the hash and a hacker will then have a very hard time * determining the original password. * <p/> * In Jive, every time a user logs in, we simply * take their plain text password, compute the hash, and compare the * generated hash to the stored hash. Since it is almost impossible that * two passwords will generate the same hash, we know if the user gave us * the correct password or not. The only negative to this system is that * password recovery is basically impossible. Therefore, a reset password * method is used instead. * * @param data the String to compute the hash of. * @return a hashed version of the passed-in String */ public static String hash(String data) { return hash(data, "MD5"); } /** * Hashes a String using the specified algorithm and returns the result as a * String of hexadecimal numbers. This method is synchronized to avoid * excessive MessageDigest object creation. If calling this method becomes * a bottleneck in your code, you may wish to maintain a pool of * MessageDigest objects instead of using this method. * <p/> * A hash is a one-way function -- that is, given an * input, an output is easily computed. However, given the output, the * input is almost impossible to compute. This is useful for passwords * since we can store the hash and a hacker will then have a very hard time * determining the original password. * <p/> * In Jive, every time a user logs in, we simply * take their plain text password, compute the hash, and compare the * generated hash to the stored hash. Since it is almost impossible that * two passwords will generate the same hash, we know if the user gave us * the correct password or not. The only negative to this system is that * password recovery is basically impossible. Therefore, a reset password * method is used instead. * * @param data the String to compute the hash of. * @param algorithm the name of the algorithm requested. * @return a hashed version of the passed-in String
⌨️ 快捷键说明
复制代码
Ctrl + C
搜索代码
Ctrl + F
全屏模式
F11
切换主题
Ctrl + Shift + D
显示快捷键
?
增大字号
Ctrl + =
减小字号
Ctrl + -