ode23tx.m

有趣的可视的数值方法 出自网站http://www.mathworks.com/moler

function [tout,yout] = ode23tx(F,tspan,y0,arg4,varargin)
%ODE23TX  Solve non-stiff differential equations.  Textbook version of ODE23.
%
%   ODE23TX(F,TSPAN,Y0) with TSPAN = [T0 TFINAL] integrates the system
%   of differential equations dy/dt = f(t,y) from t = T0 to t = TFINAL.
%   The initial condition is y(T0) = Y0.
%
%   The first argument, F, is a function handle, an inline-object in MATLAB6,
%   or an anonymous function in MATLAB7, that defines f(t,y).  This function
%   must have two input arguments, t and y, and must return a column
%   vector of the derivatives, dy/dt.
%
%   With two output arguments, [T,Y] = ODE23TX(...) returns a column 
%   vector T and an array Y where Y(:,k) is the solution at T(k).
%
%   With no output arguments, ODE23TX plots the emerging solution.
%
%   ODE23TX(F,TSPAN,Y0,RTOL) uses the relative error tolerance RTOL
%   instead of the default 1.e-3.
%
%   ODE23TX(F,TSPAN,Y0,OPTS) where OPTS = ODESET('reltol',RTOL, ...
%   'abstol',ATOL,'outputfcn',@PLOTFUN) uses relative error RTOL instead
%   of 1.e-3, absolute error ATOL instead of 1.e-6, and calls PLOTFUN
%   instead of ODEPLOT after each successful step.
%
%   More than four input arguments, ODE23TX(F,TSPAN,Y0,RTOL,P1,P2,...),
%   are passed on to F, F(T,Y,P1,P2,...).
%
%   ODE23TX uses the Runge-Kutta (2,3) method of Bogacki and Shampine (BS23).
%
%   Example    
%      tspan = [0 2*pi];
%      y0 = [1 0]';
%      MATLAB 6: F = inline('[0 1; -1 0]*y','t','y');
%      MATLAB 7: F = @(t,y) [0 1; -1 0]*y;
%      ode23tx(F,tspan,y0);
%
%   See also ODE23.

% Initialize variables.

rtol = 1.e-3;
atol = 1.e-6;
plotfun = @odeplot;
if nargin >= 4 & isnumeric(arg4)
   rtol = arg4;
elseif nargin >= 4 & isstruct(arg4)
   if ~isempty(arg4.RelTol), rtol = arg4.RelTol; end
   if ~isempty(arg4.AbsTol), atol = arg4.AbsTol; end
   if ~isempty(arg4.OutputFcn), plotfun = arg4.OutputFcn; end
end
t0 = tspan(1);
tfinal = tspan(2);
tdir = sign(tfinal - t0);
plotit = (nargout == 0);
threshold = atol / rtol;
hmax = abs(0.1*(tfinal-t0));
t = t0;
y = y0(:);

% Initialize output.

if plotit
   feval(plotfun,tspan,y,'init');
else
   tout = t;
   yout = y.';
end

% Compute initial step size.

s1 = feval(F, t, y, varargin{:});
r = norm(s1./max(abs(y),threshold),inf) + realmin;
h = tdir*0.8*rtol^(1/3)/r;

% The main loop.

while t ~= tfinal
  
   hmin = 16*eps*abs(t);
   if abs(h) > hmax, h = tdir*hmax; end
   if abs(h) < hmin, h = tdir*hmin; end
   
   % Stretch the step if t is close to tfinal.

   if 1.1*abs(h) >= abs(tfinal - t)
      h = tfinal - t;
   end
   
   % Attempt a step.

   s2 = feval(F, t+h/2, y+h/2*s1, varargin{:});
   s3 = feval(F, t+3*h/4, y+3*h/4*s2, varargin{:});
   tnew = t + h;
   ynew = y + h*(2*s1 + 3*s2 + 4*s3)/9;
   s4 = feval(F, tnew, ynew, varargin{:});
      
   % Estimate the error.

   e = h*(-5*s1 + 6*s2 + 8*s3 - 9*s4)/72;
   err = norm(e./max(max(abs(y),abs(ynew)),threshold),inf) + realmin;
      
   % Accept the solution if the estimated error is less than the tolerance.

   if err <= rtol
      t = tnew;
      y = ynew;
      if plotit
         if feval(plotfun,t,y,'');
            break
         end
      else
         tout(end+1,1) = t;
         yout(end+1,:) = y.';
      end
      s1 = s4;     % Reuse final function value to start new step.
   end
   
   % Compute a new step size.

   h = h*min(5,0.8*(rtol/err)^(1/3));
 
   % Exit early if step size is too small.
   
   if abs(h) <= hmin
      warning('Step size %e too small at t = %e.\n',h,t);
      t = tfinal;
   end
end

if plotit
   feval(plotfun,[],[],'done');
end