📄 lcross.cpp
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// crossing distribution using a linear list
#include <iostream.h>
#include "llist.h"
void main(void)
{
const int n = 10;
LinearList<int> L(n);
int K, A[n+1], B[n+1], X[n+1];
int k[11] = {0, 7, 6, 3, 1, 2, 0, 2, 0, 1, 0};
int C[n+1] = {0, 8, 7, 4, 2, 5, 1, 9, 3, 10, 6};
K = 22;
int r = K/2; // remaining number of crossings
// needed in top half
// scan wires right to left
int w = n; // w is current wire
while (r) { // need more crossings in top half
if (k[w] < r) {// use all from wire w
L.Insert(k[w], w);
r -= k[w];}
else {// use only r from wire w
L.Insert(r, w);
r = 0;}
w--;}
// determine wire permutation at center
// first w wires have same ordering
for (int i = 1; i <= w; i++)
X[i] = i;
// ordering of remaining wires is from L
for (int i = w+1; i <= n; i++)
L.Delete(1, X[i]);
// compute top half permutation
for (int i = 1; i <= n; i++)
A[X[i]] = i;
// compute bottom half permutation
for (int i = 1; i <= n; i++)
B[i] = C[X[i]];
cout << "A is ";
for (int i = 1; i <= n; i++)
cout << A[i] << ' ';
cout << endl;
cout << "B is ";
for (int i = 1; i <= n; i++)
cout << B[i] << ' ';
cout << endl;
}
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