showrecordrequesthandler.java

来自「为解决项目研发过程中Bug管理混乱、不科学以及中小型企业Bug管理过程中出现考核」· Java 代码 · 共 53 行

JAVA
53
字号
package core;

import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;

public class ShowRecordRequestHandler implements RequestHandler {
	
	SQLBean bean = new SQLBean();
	
	public ShowRecordRequestHandler(){
	}

	public String handleRequest(HttpServletRequest request,
			HttpServletResponse response) throws ServletException, IOException 
			{
		String username = request.getParameter("username");
		String password = request.getParameter("password");
		UserBean ub = bean.checkUsersLogin(username,password);
		IPUser ipu = bean.checkIPUserLogin(username,password);
		// 根据权限登录各自界面
		if(ub != null)
		{
			return "manager.jsp";
		}
		else
		{
			if(ipu != null)
			{
				// 获取该项目人员权限
				String roleRight = bean.getRight(ipu.getIp_roleId());
				if(roleRight == "1")
				{
					return "testPerson.jsp";
				}
				else if(roleRight == "2")
				{
					return "developer.jsp";
				}
//				else if(roleRight == "3")
//				{
//					return "bugOwner.jsp";
//				}
				else if(roleRight == "4")
				{
					return "reporter.jsp";
				}
				return "login.jsp";
			}
			return "login.jsp";
		}
	}
}

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