p5_42a.cpp

一个文本分析程序。实现分析一段文本中字母

// Exercise 5.42 Part A Solution
#include <iostream.h>
#include <iomanip.h>
#include <ctype.h>

const int SIZE = 80;

int main()
{
   char letters[ 26 ] = { 0 }, text[ 3 ][ SIZE ], i;
   
   cout << "Enter three lines of text:\n";
   
   for ( i = 0; i <= 2; ++i )
      cin.getline( &text[ i ][ 0 ], SIZE );
      
   for ( i = 0; i <= 2; ++i )
      for ( int j = 0; text[ i ][ j ] != '\0'; ++j )
         if ( isalpha( text[ i ][ j ] ) )
            ++letters[ tolower( text[ i ][ j ] ) - 'a' ]; 
   
   cout << "\nTotal letter counts:\n";
   
   for ( i = 0; i <= 25; ++i )
      cout << setw( 3 ) << static_cast< char > ( 'a' + i ) << ':' << setw( 3 )
           << static_cast< int > ( letters[ i ] ) << endl;

   return 0;
}