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📄 pj_oea.cpp

📁 projapi是一个关于GIS行业投影转换的程序库
💻 CPP
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#include "stdafx.h"

#ifndef lintstatic const char SCCSID[]="@(#)PJ_oea.c	4.1	94/02/15	GIE	REL";#endif#define PROJ_PARMS__ \	double	theta; \	double	m, n; \	double	two_r_m, two_r_n, rm, rn, hm, hn; \	double	cp0, sp0;#define PJ_LIB__#include	"projects.h"
#include <math.h>
PROJ_HEAD(oea, "Oblated Equal Area") "\n\tMisc Sph\n\tn= m= theta=";FORWARD(s_forward); /* sphere */	double Az, M, N, cp, sp, cl, shz;	cp = cos(lp.phi);	sp = sin(lp.phi);	cl = cos(lp.lam);	Az = aatan2(cp * sin(lp.lam), P->cp0 * sp - P->sp0 * cp * cl) + P->theta;	shz = sin(0.5 * aacos(P->sp0 * sp + P->cp0 * cp * cl));	M = aasin(shz * sin(Az));	N = aasin(shz * cos(Az) * cos(M) / cos(M * P->two_r_m));	xy.y = P->n * sin(N * P->two_r_n);	xy.x = P->m * sin(M * P->two_r_m) * cos(N) / cos(N * P->two_r_n);	return (xy);}INVERSE(s_inverse); /* sphere */	double N, M, xp, yp, z, Az, cz, sz, cAz;	N = P->hn * aasin(xy.y * P->rn);	M = P->hm * aasin(xy.x * P->rm * cos(N * P->two_r_n) / cos(N));	xp = 2. * sin(M);	yp = 2. * sin(N) * cos(M * P->two_r_m) / cos(M);	cAz = cos(Az = aatan2(xp, yp) - P->theta);	z = 2. * aasin(0.5 * hypot(xp, yp));	sz = sin(z);	cz = cos(z);	lp.phi = aasin(P->sp0 * cz + P->cp0 * sz * cAz);	lp.lam = aatan2(sz * sin(Az),		P->cp0 * cz - P->sp0 * sz * cAz);	return (lp);}FREEUP; if (P) pj_dalloc(P); }ENTRY0(oea)	if (((P->n = pj_param(P->params, "dn").f) <= 0.) ||		((P->m = pj_param(P->params, "dm").f) <= 0.))		E_ERROR(-39)	else {		P->theta = pj_param(P->params, "rtheta").f;		P->sp0 = sin(P->phi0);		P->cp0 = cos(P->phi0);		P->rn = 1./ P->n;		P->rm = 1./ P->m;		P->two_r_n = 2. * P->rn;		P->two_r_m = 2. * P->rm;		P->hm = 0.5 * P->m;		P->hn = 0.5 * P->n;		P->fwd = s_forward;		P->inv = s_inverse;		P->es = 0.;	}ENDENTRY(P)

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