6.asm

来自「华工电信系汇编习题的编程实现」· 汇编 代码 · 共 79 行

stack segment stack 'stack'
      dw 32 dup(?)
stack ends

data segment
      b1 dd 06020304H
      b2 dd 05060708H
      b3 db 5 dup(?),'$'

data ends

code segment 
begin proc far
      assume ss:stack,cs:code,ds:data
      push ds
      sub ax,ax
      push ax
      mov ax,data
      mov ds,ax

      mov al,byte ptr b1
      add al,byte ptr b2
      mov ah,0
      aaa
      add al,30H
      mov byte ptr b3 + 4,al

      mov al,byte ptr b1 + 1
      add al,ah
      mov ah,0
      aaa
      add al,byte ptr b2 + 1
      aaa
      add al,30H
      mov byte ptr b3 + 3,al

      mov al,byte ptr b1 + 2
      add al,ah
      mov ah,0
      aaa
      add al,byte ptr b2 + 2
      aaa
      add al,30H
      mov byte ptr b3 + 2,al

      mov al,byte ptr b1 + 3
      add al,ah
      mov ah,0
      aaa
      add al,byte ptr b2 + 3
      aaa
      add al,30H
      mov byte ptr b3 + 1,al

      add ah,30H
      mov byte ptr b3,ah

      mov dx,offset b3
      mov ah,9
      int 21h


      











      ret
begin   endp
code    ends
      end begin