2-13.asm
来自「华工电信系汇编习题的编程实现」· 汇编 代码 · 共 48 行
ASM
48 行
stack segment stack 'stack'
dw 32 dup(?)
stack ends
data segment
FIRST dd 0FFFFFFFBH
Forth db 4 dup(0)
data ends
code segment
begin proc far
assume ss:stack,cs:code,ds:data
push ds
sub ax,ax
push ax
mov ax,data
mov ds,ax
mov bx,word ptr FIRST + 2
mov dx,bx
and dx,0F0H
JZ ZHENG
and bh,07FH
NOT bx
mov dx,bx
mov bx,word ptr FIRST
NOT bx
add bx,1
adc dx,0
mov Forth,dh
mov Forth +1,dl
mov Forth +2,bh
mov Forth +3,bl
JMP MYEND
ZHENG:
mov bx,word ptr FIRST + 2
mov Forth,bh
mov Forth +1,bl
mov bx,word ptr FIRST
mov Forth +2,bh
mov Forth +3,bl
MYEND:
ret
begin endp
code ends
end begin
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